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FrozenT [24]
3 years ago
14

A track athlete does two and a half laps from the starting line on a track of normal shape and size. The best way to describe th

e difference between the athlete's distance versus displacement is
Physics
1 answer:
aniked [119]3 years ago
5 0

Answer:

The displacement and the distance were equal early in the run, however due to the shape of the track the distance is greater than the displacement.

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Imagine you could travel to the moon where the acceleration due to gravity is 1.6 m/s^2. What would be the period of
VladimirAG [237]

Answer:

4.9612 s

Explanation:

Applying,

T = 2π√(L/g)............... Equation 1

Where T = period of the pendulum, L = Lenght of the pendulum, g = acceleration due to gravity of the moon, π = pie.

From the question,

Given: L = 1 m, g = 1.6 m/s²

Constant: π = 3.14

Substitute these values into equation 1

T = 2×3.14×√(1/1.6)

T = 6.28√(0.625)

T = 6.28×0.79

T = 4.9612 s

6 0
3 years ago
At which of the above boundries is sea floor destroyed
Slav-nsk [51]
The continental crust
Hope it helps!!
7 0
3 years ago
2.
Phantasy [73]

Answer:

Explanation:

lll

5 0
3 years ago
Read 2 more answers
The law of universal gravitation states that any two objects in the universe, without exception,
STatiana [176]
A. attract each other.

The Law of Universal Gravitation discusses the phenomenon of gravity. Remember that gravity is the force that keeps us on Earth; the Earth pulls us down, and our bodies pull back.  Gravity is the force of attraction, so the correct answer is a).
3 0
3 years ago
The position of an electron is given by , with t in seconds and in meters. At t = 3.99 s, what are (a) the x-component, (b) the
egoroff_w [7]

Answer:

A. Vx = 3.63 m/s

B. Vy = -45.73 m/s

C. |V| = 45.87 m/s

D. θ = -85.46°

Explanation:

Given that position, r, is given as:

r = 3.63tˆi − 5.73t^2ˆj + 8.16ˆk

Velocity is the derivative of position, r:

V = dr/dt = 3.63 - 11.46t^j

A. x component of velocity, Vx = 3.63 m/s

B. y component of velocity, Vy = -11.46t

t = 3.99 secs,

Vy = - 11.46 * 3.99 = -45.73 m/s

C. Magnitude of velocity, |V| = √[(-45.73)² + 3.63²]

|V| = √(2091.2329 + 13.1769)

|V| = √(2104.4098)

|V| = 45.87 m/s

D. Angle of the velocity relative to the x axis, θ is given as:

tanθ = Vy/Vx

tanθ = -45.73/3.63

tanθ = -12.6

θ = -85.46°

7 0
3 years ago
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