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monitta
3 years ago
8

The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion fo

rces. Consider the compounds below, and classify each by its predominant attractive or intermolecular force among atoms or molecules of the same type. Identify each of the following ( NaCl, HF, HCl, F2) as Ionic, H Bonding, Dipole or Dispersion.
Chemistry
1 answer:
natima [27]3 years ago
4 0

Answer with Explanation:

Ionic bond:It is that type of bond which formed between negative and positive ions.

Hydrogen bonding:Hydrogen bonding formed between hydrogen and high electronegative elements.

Dispersion force:It is weakest intermolecular force.It is temporary attractive force.When electrons of two adjacent atoms occupy positions that make the atoms temporary dipoles.

NaCl: In which Na is positive ion and Cl is negative ion.

Therefore, NaCl is ionic.

HF:F is highest electronegativ elements.

HF:Hydrogen bonding

HCl: Hydrogen bonding

F_2:Dispersion

You might be interested in
Do you always have to begin with two compounds in a neutralization reaction
Paladinen [302]

Answer:

Yes.

Explanation:

Only an acidic compound and then a basic compound react(neutralization reaction) to give a salt.

Acid+Base=Salt+Water.

Hope this helps❤❤❤

3 0
3 years ago
What typically occurs in a substance where hydrogen bonding exists when compared to the same substance without H-bonds?
djverab [1.8K]

Answer:

B) Increase in boiling point and decrease in vapor pressure

Explanation:

Vapor pressure is inversely related  to the Boiling point , as

higher the boiling point, lower the vapor pressure. and

Lower the boiling point, higher the vapor pressure.

Hydrogen bonding.

The electrostatic attraction between Hydrogen , bonded to electronegative atom like F, O, N and the more electronegative atom is called as Hydrogen bonding.

For example -

In alcohols, - OH group has Hydrogen that is bonded to more electronegative atom O.

As ,  

Extra energy is required to break Hydrogen bonds.

because the substance which exhibits Hydrogen bonding have lower vapor pressure than that of the substance with out Hydrogen bonding.

Hence , the substance with Hydrogen bonding , has higher boiling point,.

Hence , the correct option is  Increase in boiling point and decrease in vapor pressure .

7 0
3 years ago
A closed vessel system of volume 2.5 L contains a mixture of neon and fluorine. The total pressure is 3.32 atm at 0.0°C. When th
Oxana [17]

Answer: moles of Ne = 0.149 moles

moles of F₂ = 0.221 moles

Explanation:

<em>The process occurs at costant volume.</em>

<em>Neon is a monoatomic gas, Cv =3/2R, Flourine is a diatomic gas, Cv = 5/2R</em>

n = PV/RT ; where n is total = number of moles, P is total pressure = 3.32atm, V is volume = 2.5L, R is molar gas constant = 0.08206 L-atm/mol/K = 8.314 J/mol/K, T is temperature = 0.0°C = 273.15K

n(total) = (3.32 atm)(2.5 L)/(0.08206 L-atm/mol/K)(273.15) = 0.3703 mol

For one mole heated at constant volume,

Change in entropy, ∆S = ∫dq/T = ∫(Cv/T)dT

From T1 to T2, Cvln(T2/T2) = Cvln(288.15/273.15) = 0.05346•Cv

So, for 0.3703 moles,

∆S = (0.3703 mol)(0.05346)Cv = 0.345 J/K

⇒ Cv = 17.43 J/mol/K for the Ne/F₂ mixture.

For pure Ne, Cv = (3/2)R = 1.5 • 8.314 J/mol/K = 12.471 J/mol/K

For pure F₂, Cv = (5/2)R = 2.5 • 8.314 J/mol/K = 20.785 J/mol/K

If Y is the mole fraction of Ne, Y can be determined by setting the observed entropy change (∆S) to the weighted average of the entropy changes expected for the two different gases in the mixture:

17.43 J/mol/K = Y * 12.471 J/mol/K + (1 – Y) * 20.785 J/mol/K

⇒ 20.785 J/mol/K – 8.314 J/mol/K * Y = 17.43J/mol/K

<em>Y = 0.403 ; 1 – Y = 0.597</em>

moles of Ne = (0.403)(0.3703 mol) = 0.149 moles

moles of F₂ = (0.597)(0.3703 mol) = 0.221 moles

7 0
3 years ago
What was life like in the United States during the 1930s?
liberstina [14]

The 1930s saw natural disasters as well as manmade ones: For most of the decade, people in the Plains states suffered through the worst drought in American history, as well as hundreds of severe dust storms, or "black blizzards," that carried away the soil and made it all but impossible to plant crops.

3 0
3 years ago
How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O? The reaction is:
Readme [11.4K]

Answer:

There is 5.72 grams of H2 formed

1)  C+ H2O → CO + H2

2) We start with 34 grams of carbon that will react with an excess of H2O

3) 5.72 grams of H2

Explanation:

Step 1: Data given

Mass of carbon = 34.00 grams

H2O is in excess

Molar mass of C = 12 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

C+ H2O → CO + H2

Step 3: What is the starting substance

We start with 34 grams of carbon that will react with an excess of H2O

Step 4: Calculate moles carbon

Moles C = mass C / molar mass C

Moles C = 34.00 grams / 12.00 g/mol

Moles C = 2.833 moles

Step 5: Calculate moles H2

Carbon is the limiting reactant.

For 1 mol Carbon we need 1 mol H20 to produce 1 mol CO and 1 mol H2

For 2.833 moles C we'll have 2.833 moles H2

Step 6: Calculate mass of H2

Mass H2 = moles H2 * molar mass H2

Mass H2 = 2.833 moles * 2.02 g/mol

Mass H2 = 5.72 grams of H2

8 0
4 years ago
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