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Reika [66]
2 years ago
12

How many ammonium ions and how many sulfate ions are present in an 0.260 mol sample of (nh4)2so4?

Chemistry
1 answer:
Anna11 [10]2 years ago
4 0
The question requires that you assume complete ionization of the compound. This is:

(NH4)2 SO4 → 2 NH4 (+) + SO4 (2-)

Then, 1 mol of (NH4)2 SO4 produces 3 moles of ions: 2 moles of NH4 (+) and 1 mol of SO4 (2-)

=> 0.26 * 2 moles of NH4(+) = 0.52 moles of NH4 (+)

0.26 * 1 mol of SO4 (2-) = 0.26 moles of SO4 (2-).

Answer: 0.52 moles of ammonium ions and 0.26 moles of sulfate.ions.


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Match the vocabulary with the definitions.
Fiesta28 [93]

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8 0
2 years ago
How many Mg atoms are presented in 3.00 moles of MgCl2
ella [17]

Answer:

1.81 x 10²⁴ atoms

Explanation:

To find the number of atoms in the given number of moles, we need to understand that every substance contains the Avogadro's number of particles.

More appropriately, a mole of any substance will contain the Avogadro's number of particles which is 6.02 x 10²³ atoms

 So;

           If 1 mole of a substance  = 6.02 x 10²³ atoms;

               3 mole of MgCl₂ will contain 3 x 6.02 x 10²³ = 1.81 x 10²⁴ atoms

3 0
2 years ago
the elements in group 2 have similar chemical properties because each atom of these elements has the same
Vsevolod [243]
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3 0
3 years ago
An atom that has 13 protons and 15 neutrons is an isotope of the element? How can I count it?
Diano4ka-milaya [45]
It's simple.
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and by the way ... the element which you're searching for is Aluminium
7 0
3 years ago
The half-life of Pa-234 is 6.75 hours. If a sample of Pa-234 contains 112.0 g, 1 point
umka2103 [35]

Answer:

28g remain after 13.5 hours

Explanation:

Element decayment follows first order kinetics law:

ln[Pa-234] = -kt + ln [Pa-234]₀ <em>(1)</em>

<em>Where [Pa-234] is concentration after t time, k is rate constant in time, and [Pa-234]₀ is initial concentration</em>

Half-life formula is:

t_{1/2} =  \frac{ln2}{k}

6.75 = ln2 / k

<em>k = 0.1027hours⁻¹</em>

Using rate constant in (1):

ln[Pa-234] = -0.1027hours⁻¹×13.5hours + ln [112.0g]

ln[Pa-234] = 3.332

[Pa-234] = <em>28g after 13.5 hours</em>

<em />

5 0
2 years ago
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