Question

How many ammonium ions and how many sulfate ions are present in an 0.260 mol sample of (nh4)2so4?

Answer 1

The question requires that you assume complete ionization of the compound. This is:

(NH4)2 SO4 → 2 NH4 (+) + SO4 (2-)

Then, 1 mol of (NH4)2 SO4 produces 3 moles of ions: 2 moles of NH4 (+) and 1 mol of SO4 (2-)

=> 0.26 * 2 moles of NH4(+) = 0.52 moles of NH4 (+)

0.26 * 1 mol of SO4 (2-) = 0.26 moles of SO4 (2-).

Answer: 0.52 moles of ammonium ions and 0.26 moles of sulfate.ions.