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larisa86 [58]
4 years ago
15

A physics student running 2.8 m/s increases her velocity to 4.7 m/s in 3.4 seconds. What is the magnitude of acceleration of the

student?
Physics
1 answer:
Viktor [21]4 years ago
3 0

Answer:

The magnitude of acceleration of the student is 0.6 m/s²

Explanation:

Given that,

Initial velocity = 2.8 m/s

Final velocity = 4.7 m/s

Time = 3.4 sec

We need to calculate the magnitude of acceleration of the student

Using formula of acceleration

a=\dfrac{v_{f}-v_{i}}{t}

Where, v_{f} = final velocity

v_{f} = final velocity

t = time

Put the value into the formula

a=\dfrac{4.7-2.8}{3.4}

a=0.6\ m/s^2

Hence, The magnitude of acceleration of the student is 0.6 m/s²

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