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kirill [66]
3 years ago
9

A light beam has speed c in vacuum and speed v in a certain plastic. The index of refraction n of this plastic is

Physics
1 answer:
Mnenie [13.5K]3 years ago
3 0

Answer:

n = \frac{c}{v}

Explanation:

Refractive Index: It is a measure to find how fast the light travels through a medium. It is ration of the speed of light in vacuum to speed of light in the medium. Speed of light is not constant and varies depending on the density of the medium.

In vacuum the speed of light is 300000 km/s and is denoted by c. When the light beam enters any medium the speed will decrease. Here it is given that the speed in plastic is v. Thus the refractive index(n) is given as:

n = \frac{c}{v}

It is a dimensionless no.

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A proton travels with a speed of 5.02×10⁶ m/s in a direction that makes an angle of 60.0° with the direction of a magnetic ficld
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Explanation:
the velocity ,v, of ththe proton = 5.02×10^6 m/s
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First , we need to find the magnitude of the Force on the proton. This is given by the relation :
F = q(v x B) = qvBsinθ

where 'q' is the charge of proton , q= 1.6×10^-19 C
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Putting the respective values of v, B ,θ in the above equation, we get:

F = (1.6×10^-19 C)(5.02×10^6 m/s)(0.180T) sin60°
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Now , from Newton's second law we know that ,
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(To know more about Magnetic Fields : brainly.com/question/9095546)

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