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kirill [66]
3 years ago
9

A light beam has speed c in vacuum and speed v in a certain plastic. The index of refraction n of this plastic is

Physics
1 answer:
Mnenie [13.5K]3 years ago
3 0

Answer:

n = \frac{c}{v}

Explanation:

Refractive Index: It is a measure to find how fast the light travels through a medium. It is ration of the speed of light in vacuum to speed of light in the medium. Speed of light is not constant and varies depending on the density of the medium.

In vacuum the speed of light is 300000 km/s and is denoted by c. When the light beam enters any medium the speed will decrease. Here it is given that the speed in plastic is v. Thus the refractive index(n) is given as:

n = \frac{c}{v}

It is a dimensionless no.

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Prove and state law of conservation of energy​
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In 1898, the world land speed record was set by Gaston Chasseloup-Laubat driving a car named Jeantaud. His speed was 39.24 mph (
FromTheMoon [43]

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the acceleration a^{\to} = (0.0159 \ \ m/s^2 )i

Explanation:

Given that:

the initial speed v₁ = 0 m/s i.e starting from rest ; since the car accelerates at a distance Δx = 6 miles in order to teach that final speed v₂ of 63.15 km/h.

So;  the acceleration for the first 6 miles can be calculated by using the formula:

v₂² = v₁² + 2a (Δx)

Making acceleration  a the subject of the formula in the above expression ; we have:

v₂² - v₁² = 2a (Δx)

a = \dfrac{v_2^2 - v_1^2 }{2 \Delta x}

a = \dfrac{(63.15 \ km/s)^2 - (0 \ m/s)^2 }{2 (6 \ miles)}

a = \dfrac{(17.54 \ m/s)^2 - (0 \ m/s)^2 }{2 (9.65*10^3 \ m)}

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Thus;

Assume the car moves in the +x direction;

the acceleration a^{\to} = (0.0159 \ \ m/s^2 )i

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3 years ago
A 40 kg boy is moving upwards upwards in a lift with an acceleration of 2 m /s ^2 what would be the weight felt by him if measuu
neonofarm [45]

Answer:

<h2> 48kg</h2>

f = ma \\

w \:  =  \frac{f}{g}  \\

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w =  \frac{f}{g}  \\w =   \frac{480}{10}  \\ w = 48kg

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