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Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle

LenKa [72]

Answer : The de-Broglie wavelength of this electron, $0.101\AA$

Explanation :

The formula used for kinetic energy is,

$K.E=\frac{1}{2}mv^2$ ..........(1)

According to de-Broglie, the expression for wavelength is,

$\lambda=\frac{h}{mv}$

or,

$v=\frac{h}{m\lambda}$ ...........(2)

Now put the equation (2) in equation (1), we get:

$\lambda=\frac{h}{\sqrt{2\times m\times K.E}}$ ...........(3)

where,

$\lambda$ = wavelength = ?

h = Planck's constant = $6.626\times 10^{-34}Js$

m = mass of electron = $9.11\times 10^{-31}Kg$

K.E = kinetic energy = $4.71\times 10^{-15}J$

Now put all the given values in the above formula (3), we get:

$\lambda=\frac{6.626\times 10^{-34}Js}{\sqrt{2\times 9.11\times 10^{-31}Kg\times 4.71\times 10^{-15}J}}$

$\lambda=1.0115\times 10^{-11}m=0.101\AA$

conversion used : $(1\AA=10^{-10}m)$

Therefore, the de-Broglie wavelength of this electron, $0.101\AA$

7 0

3 years ago

a student throws a coin vertically downward frok the top of a building. the coin leaves the throwers hand with a speed of 15.0m/

Elina [12.6K]

Answer:

Final speed after 2 seconds = 34.6 m/s

Explanation:

Given:

Initial speed of coin (u) = 15 m/s

Time taken = 2 seconds

Find:

Final speed after 2 seconds

Computation:

Gravitational acceleration of earth = 9.8 m/s²

Using first equation of motion;

v = u + at

or

v = u + gt

where,

v = final velocity

u = initial velocity

g = Gravitational acceleration

t = time taken

v = 15 + 9.8(2)

v = 15 + 19.6

Final speed after 2 seconds = 34.6 m/s

8 0

3 years ago

If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude

Mrrafil [7]

The magnitude of the electric field at this location is $1.5\times 10^{10} N/C$

Explanation:

Given

$Charge\ of\ the\ particle\ Q=4.3\times 10^-18\ C\\Force\ with\ which\ it\ is\ attracted\ F=6.5\times 10^-8\ N$

Electric field at this location determined by the force and charge.

E=F/Q

$E=\frac{6.5\times 10^-8}{4.3\times10^-18} =1.5\times\ 10^{10} \ N/C$

7 0

4 years ago

A(n) 77.5 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 37.3 m away from the shuttle

NeX [460]

Answer:

Explanation:

The speed of the astronaut can be found with the help of law of conservation of momentum .

mv = MV , M is mass of astronaut , m is mass of object thrown , v is velocity of object thrown and V is velocity of astronaut.

Putting the values

77.5 x V = .94 x 12

V = .14554 m /s

This will be the uniform velocity of astronaut.

Distance to be covered = 37.3 m

time taken = distance / velocity

= 37.3 / .14554

= 256.28 s

= 4.27 minutes.

4 0

3 years ago

Which of the planets do not have moons?

lubasha [3.4K]

Answer:

Mercury and Venus

Explanation:

7 0

4 years ago

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