Answer:
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
Explanation:
Given data:
Energy of photon = 1.10 × 10⁻¹³ J.
Wavelength of photon = ?
Solution:
Formula:
E = h.c / λ
λ = h. c / E
λ = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.
λ = 19.878 × 10⁻²⁶m / 1.10 × 10⁻¹³ J
λ = 18.071 × 10⁻¹³ m
λ = 18.071 × 10⁻¹³ × 10⁹
λ = 18.071 × 10⁻⁴ nm
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
Answer:
a) should be an answer that is like "matches" or "equals" or "is equal to"
b) should be "conservation of mass"
c) can't be sure because I'd need to see the answer choices, but it should be a properly balanced chemical equation (one with the same number and type of atoms on both sides)
Explanation:
I'm not positive but I'm pretty sure its Light waves.
Answer:
8,588,461,537
Explanation:
Since the atoms are arranged in a straight line in contact with each other what we have to do is divide the length into the diameter of copper (2r) to obtain the number of atoms in the 223.3 cm of copper wire, and from there we can figure how many times we wil have to divide it to answer our question.
diameter = 2 x( 1.3 x 10⁻¹⁰ m) = 2.6 x 10⁻¹⁰ m
The number of diameters in 223.3 cm ( 2.233 m ) which is the number of atoms in this length:
2.233 m / 2.6 x 10⁻¹⁰ m/atom = 8,588,461,538 atoms
So we will have to divide it 8,588,461,537 ( one minus because we want to sepate 8,588,461,538 atoms )
This is a problem where we have to work with integers and not decimals since we can not speak for example of 0.5 individual atoms