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77julia77 [94]
4 years ago
5

A book has a mass of 2.2 kilograms. what is the weight on earth?

Chemistry
1 answer:
lana66690 [7]4 years ago
6 0
<span>the answer is 21.56 N

hoped it helped !
</span>
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You have 100 grams of potassium fluoride (KF) .
laiz [17]

Answer:

Option C = 1.72 mol

Explanation:

Given data:

Mass of KF = 100 g

Moles of KF = ?

Solution:

First of all we have to calculate the molar mass of KF.

Molar mass of KF = 39.0983 g/mol + 18.998403 g/mol

Molar mass of KF = 58. 0967 g/mol

Formula:

Number of moles = mass/molar mass

Number of moles = 100 g/ 58.0967 g/mol

Number of moles = 1.72 mol

6 0
3 years ago
What is the pressure of 4 moles of helium in a 50 L tank at 308k using PV=nRT
Ilya [14]

Hey there!:

p = ??

n = 4 moles

V = 50 L

T = 308 K

R =  0.082 atm

p*V = n * R * T

p * 50 = 4 * 0.082 * 308

p*50 = 101.024

p = 101.024 / 50

p = 2.020 atm


Hope that helps!


8 0
3 years ago
Read 2 more answers
What types of metals require the use of a Roman numeral in the name of their iconic compounds
denis23 [38]
The answer is transition metals because they have no specific charge except for 1 or 2 of them
3 0
3 years ago
Read 2 more answers
Chlorine has seven electrons in its valence shell. It accepts an electron to complete its octet and becomes a chlorine ion (Cl-)
KIM [24]
The correct answer here is B - when chlorine accepts an electron to complete its octet and becomes a chlorion ion it becomes an Anion. An anion is a negatively charged ion. Chloride ions are an important electrolyte within the body.
5 0
3 years ago
Drag each tile to the correct location on the image.
nikdorinn [45]

Answer:

[He]: 2s² 2p⁵.

[Ne]: 3s².

[Ar]: 4s² 3d¹⁰ 4p².

[Kr]: 5s² 4d¹⁰ 5p⁵.

[Xe]: 6s² 4f¹⁴ 5d¹⁰ 6p².

Explanation:

  • Noble elements are used as blocks in writing the electronic configuration of other elements as they are stable elements.

  • [He]:

He contains 2 electrons fill 1s (1s²).

So, [He] can be written before the electronic configuration of 2s² 2p⁵.

  • [Ne]:

Ne contains 10 electrons fill (1s² 2s² 2p⁶).

So, [Ne] can be written before the electronic configuration of 3s².

  • [Ar]:

Ar contains 18 electrons is configured as ([Ne] 3s² 3p⁶).

So, [Ar] can be written before the electronic configuration of 4s² 3d¹⁰ 4p².

  • [Kr]:

Kr contains 36 electrons is configured as ([Ar] 4s² 3d¹⁰ 4p⁶).

So, [Kr] can be written before the electronic configuration of 5s² 4d¹⁰ 5p⁵.

  • [Xe]:

Xe contains 54 electrons is configured as ([Kr] 5s² 4d¹⁰ 5p⁶).

So, [Xe] can be written before the electronic configuration of 6s² 4f¹⁴ 5d¹⁰ 6p².

3 0
4 years ago
Read 2 more answers
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