How many particles are in 5.00 grams of nitric acid?

Why is copper (i) sulfate Cu2So4^-2? not copper (ii)?

const2013 [10]

Copper (I) oxidation state is 1 Cu2So4
copper (II) oxidation state is +2 CuSo4
copper (i) also give up one electron so you need two of them to react with the sulfate ion (which has charge of -2)
and also all metallic ions have an multiple oxidation levels corresponding to the number of electrons they can exchange or loose
Hope this helps

5 0

3 years ago

Read 2 more answers

Which statement is true of diffusion?

raketka [301]

Answer:

Molecules move from areas of high concentration to areas of low concentration.

4 0

3 years ago

The rate constant for a certain reaction is measured at two different temperatures:

Talja [164]

Answer: The activation energy Ea for this reaction is 22689.8 J/mol

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

$ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]$

$k_1$ = rate constant at temperature $T_1$ = $2.3\times 10^8$

$k_2$ = rate constant at temperature $T_2$ = $4.8\times 10^8$

$E_a$ = activation energy = ?

R= gas constant = 8.314 J/kmol

$T_1$ = temperature = $280.0^0C=(273+280)=553K$

$T_2$ = temperature = $376.0^0C=(273+376)=649K$

Putting in the values ::

$ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]$

$E_a=22689.8J/mol$

The activation energy Ea for this reaction is 22689.8 J/mol

3 0

3 years ago

How many grams of H,O are needed to produce 13 g of NaOH? 2 Na,O2 + 2 H20-4 NaOH + O2

fgiga [73]

Answer:

This is a typical stoichiometry question.To answer this question you want to get a relationship between

N

a

2

O and NaOH.

So you can get a relationship between the moles of

N

a

2

O

and moles of NaOH by the concept of stoichiometry.

N

a

2

O +

H

2

O ----------------> 2 NaOH.

According to above balanced equation we can have the stoichiometry relationship between

N

a

2

O and NaOH. as 1:2

It means 1 moles of

N

a

2

O is required to react with one mol of

H

2

O to produce 2 moles of NaOH.

in terms of mass 1 mole of

N

a

2

O has mass 62 g on reaction with water produces 2 moles of NaOH or 80 g of NaOH.

62 g of

N

a

2

O produces 80 g of NaOH.

1g of NaOH is produced from 62/80 g of

N

a

2

O

1.6 x

10

2

g of NaOH will require 62 x 1.6 x

10

2

g / 80 of

N

a

2

O

124g of

N

a

2

O.

Explanation:

3 0

3 years ago

Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the sam

mafiozo [28]

Question:

Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the same as pure water at 20.0 degrees C (18 torr). The volume of the mixture is 1.7 L and its total pressure is 0.987 atm. Determine the number of moles of hydrogen gas present in the sample.

A. 0.272 mol

B. 0.04 mol

C. 0.997 mol

D. 0.139 mol

E. 0.0681 mol

Answer:

The correct option is;

E. 0.0681 mol

Explanation:

The equation for the reaction is

Zn + HCl = H₂ + ZnCl₂

Vapor pressure of the liquid = 18 torr = 2399.803 Pa

Total pressure of gas mixture H₂ + liquid vapor = 0.987 atm

= 100007.775 Pa

Therefore, by Avogadro's law, pressure of the hydrogen gas is given by the following equation

Pressure of H₂ = 100007.775 Pa - 2399.803 Pa = 97607.972 Pa

Volume of H₂ = 1.7 L = 0.0017 m³

Temperature = 20 °C = 293.15 K

Therefore,

$n = \frac{PV}{RT} = \frac{100007.775 \times 0.0017 }{8.3145 \times 293.15} = 0.068078 \ moles$

Therefore, the number of moles of hydrogen gas present in the sample is n ≈ 0.0681 moles.

7 0

3 years ago