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Dafna11 [192]
3 years ago
5

Which two particles are found in the center of an atom?

Chemistry
2 answers:
seraphim [82]3 years ago
6 0

Answer:

B) Protons and Neutrons

Explanation:

In every atom, there is a Nucleus which contains protons and Neutrons. Protons being positive and Neutrons not having a charge (neutral).  

ivolga24 [154]3 years ago
4 0
Protons and neutrons
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What factors affect the speed of a wave? Check all that apply. the amplitude of the wave the energy of the wave the temperature
Lena [83]

Answer:

I believe its 1,2, and 5

Explanation:

4 0
3 years ago
An electrically neutral atom bears what trait?
zhenek [66]

C) It contains the same number of electrons and protons.

4 0
4 years ago
A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235
trapecia [35]

Answer : The value of \Delta E of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}

Molar mass of helium = 4 g/mole

\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole

Now we have to calculate the heat.

Formula used :

q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

c_p = specific heat of helium = 20.8 J/mol.K

T_1 = initial temperature = 310.0 K

T_2 = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

q=nc_p(T_2-T_1)

q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K

q=-19.5J

Now we have top calculate the work done.

Formula used :

w=-p\Delta V\\\\w=-p(V_2-V_1)

where,

w = work done

p = pressure of the gas = 1 atm

V_1 = initial volume = 1.21 L

V_2 = final volume = 0.99 L

Now put all the given values in the above formula, we get:

w=-p(V_2-V_1)

w=-(1atm)\times (0.99-1.21)L

w=0.22L.artm=0.22\times 101.3J=22.29J

conversion used : (1 L.atm = 101.3 J)

Now we  have to calculate the value of \Delta E of the gas.

\Delta E=q+w

\Delta E=(-19.5J)+22.29J

\Delta E=2.79J

Therefore, the value of \Delta E of the gas is 2.79 Joules.

3 0
3 years ago
Convert 19 kcal into joules
il63 [147K]

19~ \text{kcal} = 19 \times 1000 ~\text{cal } = 19000~ \text{cal} = 19000 \times 4.184~ \text{J} = 79496~ \text{J}

7 0
2 years ago
Can someone help me out please ? I am very stuck here
Alex17521 [72]
Hey there!

<span>Atomic Masses :
</span>
H = <span>1.00794  a.m.u
N = </span><span>14.0067  a.m.u
O = </span><span>15.9994  a.m.u

Therefore:

HNO3 = </span>1.00794 + 14.0067 + ( 15.9994 * 3 ) =>  <span>63.0128 g/mol</span>
7 0
4 years ago
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