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Aneli [31]
3 years ago
5

What is the average mass of a single argon atom in grams?

Chemistry
1 answer:
LiRa [457]3 years ago
6 0
 Best Answer:<span>  </span><span>The molar mass of Ar = 39.948g/mol 
1mol Ar = 6.022*10^23 atoms 
Therefore 1 atom has mass = 39.948 /(6.022*10^23) = 6.63*10^-23g</span>
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What is generally true about the compressibility of solids?
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Answer: Option (b) is the correct answer.

Explanation:

Compressibility means the ability to reduce or compress in size.

In solids, molecules are held together by strong force of attraction. Therefore, it requires very high force or energy to break the bond between the molecules of a solid.

As a result, compressibility of solids is low.

Whereas a hot ionized gas which contains same number of both positive or negatively charged electrons is known as plasma. Being a gas, molecules of plasma are not held by strong force of attractions.

Hence, plasma is compressible as compared to solids.

Thus, we can conclude that out of the given options, the statement compressibility of solids is lower than the compressibility of plasmas and gases is true.

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How many liters of oxygen gas, at standard
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Answer:

Explanation:

  • For the balanced reaction:

<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)​.</em>

It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

  • Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:

no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.

  • Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

<em><u>Using cross multiplication:</u></em>

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.

  • Finally, we can get the volume of oxygen using the information:

<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>

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<em><u>Using cross multiplication:</u></em>

1 mol of O₂ occupies → 22.4 L, at STP conditions.

0.48 mol of O₂ occupies → ??? L.

∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.

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