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Luda [366]
3 years ago
15

1. An object 20 cm away from a lens produces a focused image on a film 15 cm away, what is the focal length

Physics
1 answer:
morpeh [17]3 years ago
6 0

8.6 cm

Explanation:

Step 1:

In this we have to find the focal length of converging lens.

To find focal length we have,

(1/u) + (1/v) = (1/f)

where u = Object distance

           v= Image distance

           f = Focal length

Step 2:

(1/f) = (1/20) + (1/15)

(1/f) =  0.116

f = 1/0.116

f = 8.6 cm

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Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts
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(a) The system of interest if the acceleration of the child in the wagon is to be calculated are the wagon and the children outside the wagon.

(b) The acceleration of the child-wagon system is 0.33 m/s².

(c) Acceleration of the child-wagon system is zero when the frictional force is 21 N.

<h3>Net force on the third child</h3>

Apply Newton's second law of motion;

∑F = ma

where;

  • ∑F is net force
  • m is mass of the third child
  • a is acceleration of the third child

∑F = 96 N - 75 N - 12 N = 9 N

Thus, the system of interest if the acceleration of the child in the wagon is to be calculated are;

  • the wagon
  • the children outside the wagon

<h3>Free body diagram</h3>

           →                 →              Ф                         ←

         1st child      friction       wagon                2nd child

<h3>Acceleration of the  child and wagon system</h3>

a = ∑F/m

a = 9 N / 27 kg

a = 0.33 m/s²

<h3>When the frictional force is 21 N</h3>

∑F = 96 N - 75 N - 21 N = 0 N

a = ∑F/m

a = 0/27 kg

a = 0 m/s²

Learn more about net force here: brainly.com/question/14361879

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2 years ago
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Explanation:

When the child is tossed up into the air then she gains kinetic energy as the child has moved from its initial position.

It is given that mass is 20 kg, velocity is 5 m/s^{2}, and height is 2 m.

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             kinetic energy = \frac{1}{2}mv^{2}

                                      = \frac{1}{2}20 kg \times (5 m/s)^{2}

                                      = 10 kg \times 25 m^{2}/s^{2}

                                      = 250 kg m^{2}/s^{2}

Also, when child falls off the ground then she will have gravitational potential energy.

Calculate gravitational potential energy of child as follows.

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                                         = 392 kg m^{2}/s^{2}

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