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SCORPION-xisa [38]
3 years ago
9

Which atomic orbitals overlap to form the C-O bond of dimethyl ether, (CH3)20? O c 2sp^3 + 2sp^3 OC 2sp^2 + 0 2p O c 2sp^2 + 0 2

5p^2 O C 2sp^3 + O 2sp?
Chemistry
1 answer:
Mumz [18]3 years ago
4 0

Answer:

C 2sp³ + 2sp³ O

Explanation:

Carbon has an atomic number equal to <em>6</em>, so its electronic distribution is:

1s²2s²2p²

Oxygen has an atomic number equal to <em>8</em>, so its electronic distribution is:

1s²2s²2p⁴

In dimethyl ether, the bonds between carbon and hydrogen and carbon and oxygen are saturated, so there will be only sigma bonds. The sigma bonds occurs in hybrids orbitals, and pi bonds on normal orbitals. So, the carbons and the oxygen of that compound has hybridization

2sp³, because they need 4 hybrid orbitals.

So the bond C-O occurs between C 2sp³ + 2sp³ O

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If we mix 25 grans if sodium oxide with a large amount of potassium chloride, how many grams of sodium chloride should be produc
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Answer:

47.2 g

Explanation:

Data given:

mass of Sodium oxide (Na₂O) = 25 grams

mass of potassium chloride (KCl) = excess

amount of sodium chloride (NaCl) = ?

Solution:

First we look for reaction of sodium oxide with potassium chloride.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

As we know that potassium chloride is in excess amount and sodium oxide is 25 g so it means sodium oxide is a limiting reactant and amount of sodium chloride depends on the amount of sodium oxide.

So, now we will look for mole mole ration of Na₂O to NaCl.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

                    1 mol                              2 mol

from above equation we come to know that 1 mole of Na₂O gives 2 moles of NaCl.

Now convert moles to mass

As we Know

Molar mass of Na₂O = 2(23) + 16 = 62 g/mol

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

So

                  Na₂O              +   2 KCl    ----------->      2 NaCl          +      K₂O

             1 mol (62 g/mol)                                   2 mol (58.5 g/mol)

                  62 g                                                          117 g

So, it means that 62 g of Na₂O produce 117 g of NaCl then how many grams of NaCl will be produce by 25 g of Na₂O

Apply unity formula

                           62 g of Na₂O ≅ 117 g of NaCl

                           25 g of Na₂O ≅ X g of NaCl

Do cross multiplication

                          X g of NaCl = 117 g x 25 g / 62 g

                          X g of NaCl = 47.2 g

So,

25 g of Na₂O gives 47.2 grams of NaCl.

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