The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.
The reaction is:
2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O (1)
The enthalpy of reaction (1) is given by:
(2)
Where:
r: is for reactants
p: is for products
The bonds of the compounds of reaction (1) are:
- 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
- 7O₂: 7 moles of 1 O=O bond
- 4CO₂: 4 moles of 2 C=O bonds
- 6H₂O: 6 moles of 2 H-O bonds
Hence, the enthalpy of reaction (1) is (eq 2):
![\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol](https://tex.z-dn.net/?f=%20%5CDelta%20H%20%3D%20%5B2%2A%286%2A413%20%2B%20347%29%20%2B%207%2A498%20-%20%284%2A2%2A799%20%2B%206%2A2%2A467%29%5D%20kJ%2Fmol%20)
Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.
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B: The total thermal energy is greater in a large body of water than one much smaller
Explanation:
A large lake filled filled with cool water will have more thermal energy than smaller pond filled with warmer water because the total thermal energy is greater in a large body of water than one that is much smaller.
Thermal energy is a form of kinetic energy usually due to transfer of heat energy.
Amount of heat energy is dependent on the differences in temperature, mass and specific heat capacity of a body.
Both lake water will have the same specific heat capacity. Since larger body of water has more mass, it will possess more thermal energy.
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Specific heat capacity brainly.com/question/7210400
Thermal energy brainly.com/question/914750
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Answer:
0.35714 Metric ton
Explanation:
350 / 0.98 = 357.1 ----------A
to get the answer on metric ton divide (a) by 1000
357.14/1000= 0.357
First gap is BY USING MAGNETS
2nd is ELECTROLYSIS
3rd is EVAPORATION
Answer:
pOH=9.9
Explanation:
pH=-log[H+]= -log[0.0000877]
=4.06
pOH+ pH=14
pOH=14-4.06= 9.91
