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3 years ago

What drives this process

Chemistry

2 answers:

m_a_m_a [10]3 years ago

8 0

Answer:

Explanation:

cool air never rises so not A

C would mean its getting warmer

and heat flows from warm to cool so not D

we are left with B

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nikklg [1K]3 years ago

3 0

The answer to your question is C.
Convection currents in the air.

This phenomena is called an offshore breeze. At night, land is cooling faster than water; the air above the land also cools and, therefore, its density grows. As a result, the pressure above the land is greater than above the water, and the air moves from the regions with higher pressure (land) to the ones with lower pressure (water).

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A cube made of platinum (Pt) has an edge length of 1.0 cm. (a) Calculate the number of Pt atoms in the cube. (b) Atoms are spher

irina1246 [14]

Answer:

a)The total number of platinum atoms are $6.620\times 10^{22} atoms$ .

b)The radius of a Pt atom is 138.7 pm.

Explanation:

a) Let the total number of platinum atoms be x

And mass of x atoms of platinum be m

Edge length of platinum cube ,s= 1.0 cm

Volume of the cube = $1.0 cm^3$

Density of the platinum cube = $d=21.45 g/cm^3$

Mass = Density × Volume

$(m)=21.45 g/cm^3\times 1.0 cm^3=21.45 g$

Mass of an atom of platinum = $3.240\times 10^{-22} g$

$x\times 3.240\times 10^{-22} g=21.45 g$

$x=6.620\times 10^{22} atoms$

b) If only 74 percent of the space inside the cube is taken up by Pt atoms.

Volume occupied by platinum atoms = 74% of $1.0 cm^3$

$V'= 0.74 cm^3$

Volume occupied by $6.620\times 10^{22}$ atoms is $0.74 cm^3$ .

$6.620\times 10^{22} \times \frac{4}{3}\pi r^3=V'$

$6.620\times 10^{22} \times \frac{4}{3}\times 3.14\times r^3=0.74 cm^3$

$r = 1.387\times 10^{-8} m = 138.7 pm$

The radius of a Pt atom is 138.7 pm.

3 0

3 years ago

i don't need these solved I just need the steps to solve it and. what these problems in chemistry would be called so I can look

wolverine [178]

The answers are as follows,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr

<u>Explanation:</u>

All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.

It can be expressed as follows,

P1V1 = P2V2

Rearranging the above expression, we get,

$$ V2 = \frac{P1V1}{V2}$

1) The first case can be solved as,

$$V 2=\frac{921 \mathrm{mm} \mathrm{Hg} \times 3.89 \mathrm{L}}{760 \mathrm{mm} \mathrm{Hg}}=4.71 \mathrm{L}$

2) The second case can be solved as,

$$V 2=\frac{25 L \times 600 \text { torr}}{4560 \text { torr}}=3.29 L$

3) The third case can be solved as,

$$P 2=\frac{7.43 L \times 1100 \text { torr}}{5 L}=1634.6 \text { torr}$

Thus the answers for all the three cases are found as,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr respectively

6 0

3 years ago

A catalyst is:

icang [17]

A catalyst is a substance that increases the rate of a chemical reaction without itself being consumed . (ans: second choice)

7 0

2 years ago

Read 2 more answers

Sodium carbonate (NaCO3) is sometimes used as a water-softening agent. Suppose that a worker prepares a 0.730 M solution of NaCO

elena55 [62]

Answer : The mass of solute in solution is $1.09\times 10^2g$ .

Solution : Given,

Molarity = 0.730 M

Volume of solution = 1.421 L

Molar mass of sodium carbonate = 105.98 g/mole

Formula used for Molarity :

$Molarity=\frac{w}{M\times V}$

where,

w = mass of solute

M = Molar mass of solute

V = volume of solution in liter

Sodium carbonate is solute and water is solvent.

Now put the given values in above formula, we get the mass of solute in solution.

$0.730mole/L=\frac{w}{(105.98g/mole)\times (1.412L)}$

By rearranging the terms, we get

$m=109.247g=1.09\times 10^2g$

Therefore, the mass of solute in solution is $1.09\times 10^2g$ .

4 0

3 years ago

What are the relationships between temperature and viscosity of water?

iris [78.8K]

Explanation:

Both cohesion and molecular interchange contribute to liquid viscosity. The impact of increasing the temperature of a liquid is to reduce the cohesive forces while simultaneously increasing the rate of molecular interchange. The former effect causes a decrease in the shear stress while the latter causes it to increase.

temperature?

The viscosity of liquids decreases rapidly with an increase in temperature, and the viscosity of gases increases with an increase in temperature. Thus, upon heating, liquids flow more easily, whereas gases flow more sluggishly.

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8 0

3 years ago