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Sever21 [200]
3 years ago
5

: How much energy is required to heat an iron nail with a mass of 25.5 grams from 65°C until it becomes red hot at 720°C?

Chemistry
1 answer:
Evgen [1.6K]3 years ago
8 0

Q = mct  

-Q= energy in Joules  

-m = mass in grams  

-c= specific heat capacity in J/g degree C  

-t = delta temperature in degrees Celsius  

So,  

Q = m c t  

Q = (7 grams)(0.448J/g C)(750 C - 25 C)  

Q = 2273.6 J  

Your final answer = 2273.6 Joules

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Please help me out i don’t get this. what is the answers to 1-4.
VLD [36.1K]

Answer:

1. A circuit is a path that electricity flows along. It starts at a power source, like a battery, and flows through a wire to a light bulb or other object and back to other side of the power source.

2. A series circuit is one that has more than one resistor, but only one path through which the electricity (electrons) flows. All the components in a series circuit are connected end-to-end. A resistor in a circuit is anything that uses some of the power from the cell.

3. A parallel circuit is a circuit in which the electric current passes through two or more branches or connected parts at the same time before it combines again. Compare.

4. BOTH - 1. lightbulb 2. battery 3. switch

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i'm not sure about the rest sorry :(

7 0
2 years ago
The energy source used in nuclear power plants today is
Klio2033 [76]

Answer:

B I have taken the quiz already 90%

7 0
3 years ago
If you are traveling at 60mi/hr, how many meters per second is that equivalent to?
lesya [120]

Answer:

26.8224 Meters per Second.      

5 0
1 year ago
Which of the following is Not true of atoms?
Amanda [17]

Answer:

b

Explanation:

atom combine to form molecules to attain stable configuration

7 0
3 years ago
Read 2 more answers
Help?
Ahat [919]

Answer:

KClO_3

Explanation:

Hello!

In this case, as we know the mass of the total sample, we can first compute the mass of oxygen:

m_O=22.9g-7.33g-6.65g=8.92g

Next, we compute the moles of each element:

n_K=\frac{7.33g}{39.9g/mol}= 0.184mol\\\\n_{Cl}=\frac{6.65g}{35.45g/mol}=0.188mol \\\\n_O=\frac{8.92g}{16.00g/mol} =0.5575mol

Now, we divide the moles by 0.184 moles, the fewest ones, to obtain:

K=\frac{0.184}{0.184}=1.0 \\\\Cl=\frac{0.187}{0.184}=1.0\\\\O=\frac{0.5575}{0.184}  =3.0

Therefore, the empirical formula is:

KClO_3

Regards!

3 0
2 years ago
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