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Sever21 [200]
3 years ago
5

: How much energy is required to heat an iron nail with a mass of 25.5 grams from 65°C until it becomes red hot at 720°C?

Chemistry
1 answer:
Evgen [1.6K]3 years ago
8 0

Q = mct  

-Q= energy in Joules  

-m = mass in grams  

-c= specific heat capacity in J/g degree C  

-t = delta temperature in degrees Celsius  

So,  

Q = m c t  

Q = (7 grams)(0.448J/g C)(750 C - 25 C)  

Q = 2273.6 J  

Your final answer = 2273.6 Joules

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In the final stage of the nuclear fuel cycle, the spent fuel must be transported, processed, and disposed of properly. True Fals
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True
After the process of Ore processing, Enrichment, Fuel production and being passed through the reactor core the last remaining step is spent fuel disposal. 
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3 years ago
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1. What is one of the important roles of tropical rainforests in the earth's environment?
Makovka662 [10]

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1.D

2.C

3.D

4.D

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6 B

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3 years ago
Does water added to a flask containing chlorine gas and solid sodium react in the chemical reaction to make sodium chloride
Jet001 [13]

Answer:

Explanation:

Chemically, we can have a reaction between chlorine gas and solid sodium

This reaction is actually explosive and would produce fine powder of sodium chloride

We have the reaction as follows:

2Na_{(s)}+Cl_{2(g)}\rightarrow2NaCl_{(s)}

Essentally, what we can deduce from here is that we do not need to add water to the flask. Except for the reason that we would want the sodium chloride solid in the solution form, there is absolutely no reason to add water to the flask as the reaction would proceed normally

5 0
1 year ago
Which elements on the periodic table fulfill the octet rule​
horsena [70]

Answer:

Noble Gases

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8 0
3 years ago
Could someone explain how they got this answer, explain step by step plz
gulaghasi [49]

Answer:

6.018 amu

Explanation:

Let 6–Li be isotope A.

Let 7–Li be isotope B.

Let the abundance of 6–Li be A%

Let the abundance of 7–Li be B%

The following data were obtained from the question:

Atomic mass of isotope A (6–Li) =.?

Atomic mass of isotope B (7–Li ) = 7.015 amu.

Abundance of 7–Li (B%) = 92.58%

Abundance of 6–Li (A%) = 100 – B% = 100 – 92.58 = 7.42%

Atomic mass of Lithium = 6.941amu

The atomic mass of isotope A (6–Li) can be obtained as follow:

Atomic mass = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

6.941 = [(mass of A x 7.42)/100] + [(7.015x92.58)/100]

6.941 = [(mass of A x 7.42)/100] + 6.494487

(mass of A x 7.42)/100 = 6.941 – 6.494487

(mass of A x 7.42)/100 = 0.446513

Mass of A x 7.42 = 100 x 0.446513

Mass of A x 7.42 = 44.6513

Divide both side by 7.42

Mass of A = 44.6513 / 7.42

Mass of A = 6.018 amu

Therefore, the mass of 6–Li is 6.018 amu

7 0
3 years ago
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