Answer:
hope it helps cuz i did not really understand
2H₂ + O₂ = 2H₂O
n(H₂)=m(H₂)/M(H₂)
n(H₂)=5g/2.0g/mol=2.5 mol
n(O₂)=m(O₂)/M(O₂)
n(O₂)=40g/32.0g/mol=1.25 mol
H₂ : O₂ = 2 : 1
2.5 : 1.25 = 2 : 1
n(H₂O)=n(H₂)=2n(O₂)=2.5 mol
m(H₂O)=n(H₂O)M(H₂O)
m(H₂O)=2.5mol*18.0g/mol=45.0 g
Answer:
X₂O₃ , Y₂O
Explanation:
Valency of an element tells how well that element can form compounds with other atoms.
It sometimes, is also determined by the number of hydrogen atoms that it combines with.
Oxygen usually has a valency of 2, or oxidation state of -2.
That means oxygen will need 2 more electrons in it's outer shell to form a configuration of a noble gas(octet configuration).
The oxidation state of an atom in a molecule gives the number of valence electrons it has gained or lost.
Assuming both X and Y are less electronegative than oxygen, X has a valency of 3 and OS of +3.
While forming a neutral compound, we need no net charge on the compound. In X₂O₃,
total charge on X is 2 x (OS of X)= 2 x ( +3) = +6
total charge on O is 3 x (OS of O)= 3 x ( -2) = -6
Net charge is 0.
Similarly, in Y₂O
total charge on Y is 2 x (OS of Y)= 2 x ( +1) = +2
total charge on O is 1 x (OS of O)= 1 x ( -2) = -2
Net charge is 0.
The question is incomplete. the complete question is:
A chemistry student needs 35.0 g of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is . Calculate the volume of pentane the student should pour out.Round your answer to 3 significant digits.
Answer: The volume of pentane the student should pour out is 55.9 ml
Explanation:
Density is defined as the mass contained per unit volume.
To calculate volume of a substance, we use the equation:
We are given:
Density of pentane =
Mass of pentane = 35.0 g
Putting values in above equation, we get:
(Conversion factor: )
Hence, the volume of pentane is 55.9 ml