Ask question

Ask question

All categories

3 years ago

8

People cut down a forest to bulid a housing development which of the following describes how this action will likely affect the

water cycle for this region

1 answer:

Ratling [72]3 years ago

8 0

Answer:

It would mean less transpiration and the groundwater would start to make a landslide with no tree root to hold the earth in place

You might be interested in

When it is summer at the South Pole,

Elza [17]

D

The northern hemisphere is experiencing winter because it is tilted away from the sun whereas the south experiences summer because it is tilted towards the sun

6 0

3 years ago

The number of employees for a certain company has been decreasing each year by 4%. If the company currently has 650 employees an

nika2105 [10]

The answer would probably be 649.96

8 0

3 years ago

Which of the following cars have the most kinetic energy

faltersainse [42]

<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>

$\huge\boxed{OptionA}$

<h2>_____________________________________</h2><h2>DATA:</h2><h3>Blue Car: </h3>

mass = 4 kg

velocity = 5 m/s^2

<h3 /><h3>Orange truck:</h3>

Mass= 2kg

Velocity = 7m/s^2

<h3 /><h3>Grey Car:</h3>

mass = 6 kg

velocity = 4m/s^2

<h3 /><h3>Green Car:</h3>

Mass = 8 kg

Velocity = 3 m/s^2

<h2>_____________________________________</h2><h2>SOLUTION:</h2>

By the equation of kinetic energy,

K.E = $\frac{1}{2} mv^2$

Where,

K.E is kinetic energy

m is mass

v is velocity

<h2>_____________________________________</h2><h3>Kinetic energy of Blue car:</h3>

Directly substitute the variables in the equation,

K.E = $\frac{1}{2}x4x5^2$

Simplify the equation,

K.E = 50 J

<h2>_____________________________________</h2><h3>Kinetic Energy of Silver Car:</h3>

Directly substitude the variable in the equation,

K.E = $\frac{1}{2}x6x4^2$

Simplify the equation,

K.E = 48J

<h2>_____________________________________</h2><h3>Kinetic Energy of Green Car:</h3><h3 />

Substitute the variables in the equation,

K.E = $\frac{1}{2}x8x3^2$

Simplify the Equation,

K.E = 36J

<h2>_____________________________________</h2><h3>Kinetic Energy of Orange Truck:</h3><h3 />

Substitute the variable,

K.E = $\frac{1}{2}x 2x7^2$

Simplify the equation,

K.E = 49J

<h2>_____________________________________</h2>

As you can see that the highest value of kinetic energy is of Blue SUV thus it will be out answer.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h3 /><h3 /><h3 /><h3 /><h2 /><h2 />

6 0

3 years ago

A particle of mass.25 kg is moving with a speed of 7m/s due north.find it's kinetic energy.<br>

Ivenika [448]

Answer:

Explanation:

612J

3 0

3 years ago

A 3500 kg spaceship is in a circular orbit 220 km above the surface of Earth. It needs to be moved into a higher orbit of 360 km

Vitek1552 [10]

Answer:

The work done is calculated as $0.044\times 10^{11}\ J$

Solution:

As per the question:

Mass of the spaceship, m = 3500 kg

Height of the orbit, h = 220 km

Mass of the earth, $M_{e} = 5.97\times 10^{24}\ kg$

Height of the higher orbit, h' = 360 km

Radius of the orbit, $R = 6.37\times 10^{6}\ km$

Now,

The work done is given by the change in the gravitational potential energy:

Gravitational Potential Energy, U = $- \frac{GM_{e}m}{R + h}$

Now, for the lower orbit:

$U_{l} = - \frac{GM_{e}m}{R + h}$

$U_{l} = - \frac{6.67\times 10^{- 11}\times 5.97\times 10^{24}\times 3500}{6.37\times 10^{6} + 220\times 10^{3}}$

$U_{l} = - 2.115\times 10^{11}\ J$

For upper orbit:

$U_{U} = - \frac{GM_{e}m}{R + h}$

$U_{u} = - \frac{6.67\times 10^{- 11}\times 5.97\times 10^{24}\times 3500}{6.37\times 10^{6} + 360\times 10^{3}}$

$U_{U} = - 2.071\times 10^{11}\ J$

Change in the gravitational Potential energy:

$\Delta U = U_{U} - U_{l} = - 2.071\times 10^{11} - (- 2.115\times 10^{11}) = 0.044\times 10^{11}\ J$

Therefore, the work done:

$W = 0.044\times 10^{11}\ J$

7 0

3 years ago