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3 years ago

Which of these is a simplified form of the equation 7z + 2 = 8 + 2z + 1z?

Mathematics

2 answers:

WINSTONCH [101]3 years ago

4 0

Simplify it and compare

(7-2-1) z = 8 - 2

4z = 6

so the 3rd

Maru [420]3 years ago

3 0

Answer : The simplified form of the equation is, 4z = 6

Step-by-step explanation:

As we are given the expression of equation. Now we have to simplified this expression.

The given expression is:

7z + 2 = 8 + 2z + 1z

Taking like terms together.

7z - 2z - 1z = 8 - 2

By solving the expression, we get:

4z = 6

Hence, the simplified form of the equation is, 4z = 6

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The sum of five times a number and 6 is 21. What is the number?

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Answer: it’s 3

Step-by-step explanation:

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4 years ago

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Q1 : Find the inverse of the function.

Mamont248 [21]

Answer:

1. Option D is correct.

2. Option B is correct.

3. Option B is correct.

Step-by-step explanation:

Inverse function defined as the the function that undergoes the action of the other function.

A function $f^{-1}$ is the inverse of f if whenever y =f(x) and $x =f^{-1}$

To find the inverse of the function:

Q1.

Given the function: f(x) = 7x -1

Put y for f(x) and solve for x;

y= 7x -1

Add 1 both sides we get;

y + 1 = 7x

Divide both sides by 7 we get;

$x = \frac{y+1}{7}$

Put $f^{-1}(y)$ for x;

$f^{-1}(y) = \frac{y+1}{7}$

Interchange y =x, we have

$f^{-1}(x) = \frac{x+1}{7}$

Q 2.

Given the function:

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Put y for f(x) and solve for x;

$y = x^3-7$

Add 7 both sides we get;

$y + 7 =x^3$

taking cube root both sides we get

$x =\sqrt[3]{y+7}$

Put $f^{-1}(y)$ for x;

$f^{-1}(y) =\sqrt[3]{y+7}$

Interchange y =x, we have

$f^{-1}(x) = \sqrt[3]{x+7}$

Q3 .

Given the function:

$f(x) = 5x^3 - 3$

Put y for f(x) and solve for x;

$y = 5x^3-3$

Add 3 both sides we get;

$y + 3 =5x^3$

Divide both sides by 5 we get;

$x^3 = \frac{y+3}{5}$

taking cube root both sides we get

$x = \sqrt[3]{\frac{y+3}{5} }$

Put $f^{-1}(y)$ for x;

$f^{-1}(y) = \sqrt[3]{\frac{y+3}{5} }$

Interchange y =x, we have

$f^{-1}(x) = \sqrt[3]{\frac{x+3}{5} }$

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Answer:

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