Answer:
The time decreases steadily
Explanation:
We know that the rate of chemical reaction is defined as how fast or slow a chemical reaction proceeds. Hence a chemical reaction is said to proceed at a faster rate if it takes a lesser time for the reaction to get to completion.
There are certain factors that affects the rate of reaction, prominent among them is the concentration of reactants. Concentration simply means the amount of substance in a system.
Taking a look at the table given in the question, we will realize that the volume of HCl remained constant, the volume of thiosulphate increased steadily while the volume of water decreased steadily. Remember that concentration increases when less water is added to the system. This implies that the reactant concentration increases steadily. Hence, according to the collision theory, particles collide more frequently and the rate of reaction increases.
As the rate of reaction increases, it now takes a lesser time for the reaction to get to completion (indicated by the disappearance of the cross). Hence as we move down the table, it takes lesser and lesser time for the cross to disappear. This means that the column for time will decrease steadily.
We can assume that all<span> gravitational potential energy is converted into
kinetic energy of the object.</span><span>
<span>Hence, </span>GPE = KE
Where GPE is gravitational Potential Energy (J)
and KE is Kinetic Energy (J)
GPE = mgh
<span>Where, m is the mass of the object (kg), g is acceleration due to gravity (9.8 m s</span></span>⁻<span>²) and h is the height to the<span> object from ground (m).</span></span><span>
m = 0.18 kg
g = 9.8 m s</span>⁻²<span>
h = 45 m
Hence,
GPE = 0.18 kg x 9.8 m s</span>⁻² x 45 m<span>
= 79.38 J
≈ 79 J
<span>Hence, </span>KE = GPE = 79 J
<span>Hence, the
answer is '79 joules'.</span></span>
Answer:
Explanation:
Balanced equation: CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)
We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products
(a) Enthalpies of formation of reactants and products
(b) Total enthalpies of reactants and products
(c) Enthalpy of reaction
Answer:
0.019 g.
Explanation:
- Firstly, we need to find the no. of moles of oxygen gas:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm (P = 1.02 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).
∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.
- To find the mass of oxygen gas, we have:
<em>no. of moles = mass/molar mass.</em>
<em></em>
∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.
It’s called An alkyl group.
