Winds transfer energy in the form heat from the air to the ground!
Here are the steps you would need to follow:
#1). Define what 'the 'X is, and how it's related to the ball.
#2). Be clear on how 'the X' is related to the 'known velocity'.
#3). Identify how the 'known velocity' is related to the action of the ball when it's launched.
With this information in front of you, you'll have a much better chance
of answering the question.
With none of it in front of me, I have no chance at all.
Argon<span> gas is used in fluorescent and incandescent light </span>bulbs<span> to stop the oxygen in the light </span>bulbs<span> from corroding the hot tungsten filament.The use of </span>argon<span> in light</span>bulbs<span> prevents the evaporation of the tungsten filaments, which results in increased light </span>bulb<span> life.</span>
As you approach the surface of the sphere very closely, the electric field should resemble more and more the electric field from an infinite plane of charge.
If you check Gauss's law (recalling that the field in the conductor is zero) you will see that if the surface charge density is σ=Q/4πR2, then indeed the field at the surface is σ/ϵ0 as in the infinite charge of plane case.
Such a field is constant, the field lines are parallel and non-diverging, and the infinities associated with the field due to point charge do not arise.
Explanation:
