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bazaltina [42]
3 years ago
6

A car on a freeway speeds up to get around another car. The car speeds up from 20 m/s to 35 m/s in 5 seconds.

Physics
1 answer:
Tanzania [10]3 years ago
5 0

Answer:

Initial speed = 20 m/s

Final speed = 35 m/s

Time to speed up = 5 seconds

Explanation:

Directly from the information given:

Initial speed = 20 m/s

Final speed = 35 m/s

Time to speed up = 5 seconds

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On the Moon, the acceleration due to the effect of gravity is only about 1/6 of that on Earth. An astronaut whose weight on Eart
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And on the moon, the with is 595/6 N
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A pendulum is made by letting a 4 kg mass swing at the end of a string that has a length of 1.5 meter. The maximum angle that th
olga nikolaevna [1]

Answer:

Approximately 7.8\; \rm J.

Explanation:

The change in the gravitational potential energy of the pendulum is directly related to the change in its height.

Refer to the sketch attached. The pendulum is initially at \rm P_2. Its highest point is at P_1. The length of segment \rm BP_2 gives the change in its height.

The lengths of \rm AP_1 and \rm AP_2 are simply the length of the string, 1.5\; \rm m. To find the length of \rm BP_2, start by calculating the length of \rm AB.

\rm AB forms a leg in the right triangle \rm \triangle AP_1B. Besides, it is adjacent to the 30^\circ angle \rm P_1\hat{A}B. Its length would be:

\rm AB = 1.5 \times \cos(30^\circ) \approx 1.30\; \rm m.

The length of \rm BP_2 would thus be

\rm BP_2 = AP_2 - AB = 1.5 - 1.30 \approx 0.20\; \rm m.

The change in gravitational potential energy can be found with the equation

\Delta \mathrm{GPE} = m \cdot g \cdot \Delta h. In this equation,

  • m is the mass of the object,
  • g \approx 9.81\; \rm N \cdot kg^{-1} near the surface of the earth, and
  • \Delta h is the change in the object's height.

In this case, m = 4\; \rm kg and \Delta h \approx 0.20\; \rm m. Therefore:

\Delta \mathrm{GPE} = 4 \times 9.81 \times 0.20 \approx 7.8\; \rm J.

6 0
3 years ago
What is the speed of sound at sea level?
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The speed of sound at sea level is 340.29 m/s (meters per seconds).
7 0
4 years ago
At a height of ten meters above the surface of a freshwater lake, a sound pulse is generated. The echo from the bottom of the la
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Answer:

Explanation:

Velocity of sound in air at 20 degree = 343 m/s

Velocity of sound in water at 20 degree = 1470 m/s

Time taken in to and fro movement in air

=( 2 x 10) / 343 = 0.0583 s

Rest of the time  is

.171 - .0583 = .1127 s

This time is taken to cover distance in water. If d be the depth of lake

2d / velocity = time taken

2 d / 1470 = .1127

d = 82.83 m

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3 years ago
What particles bond together to
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Answer:

atoms bond together and forms molecules

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