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lbvjy [14]
3 years ago
13

if you have several different substances mixed together, like Italian salad dressing, where do the most dense materials go where

do the least dense materials go
Physics
1 answer:
Alecsey [184]3 years ago
5 0
If you've ever mixed water and oil together,you've probably noticed that the oil rises to the top and the water stays at the bottom-- no matter how much you try to shake them. This is because oil is less dense than water, making it float to the top. The molecules in oil are larger than those in water, so they don't pack as tightly together as they do in water. In a mixture of oil and vinegar, the<span> </span>oil <span>floats on the </span>vinegar/<span>water mixture, while the solids sink to the bottom. So, if one material floats over another, the material on top is less dense. 

Let me know if this helps! :)</span>
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We calculated the speed of visible light through four substances. What is different about the substances? Lesson: 4.10 Substance
marusya05 [52]

Answer:

it's to dense

Explanation:

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3 years ago
A ball starts from rest and rolls down a hill at a constant acceleration of 5 m/s2. If it travels for 8 m how fast is it going i
makkiz [27]

Hi there!

We can use the following kinematic equation:

v_f^2 = v_i^2 + 2ad

vf = final velocity (? m/s)
vi = intial velocity (0 m/s)

a = acceleration (5 m/s²)

d = displacement (8 m)

Plug in the givens and solve.

v_f^2 = 0 + 2(5)(8)\\\\v_f = \sqrt{80} = \boxed{8.944 \frac{m}{s}}

5 0
3 years ago
In which electric circuit would the voltmeter read 10 volts ?
ki77a [65]

Given that,

Voltage = 10 volt

Suppose, The three resistance is connected in parallel and each resistance is 12 Ω. find the current in the electric circuit.

We need to calculate the equivalent resistance

Using formula of parallel

\dfrac{1}{R}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}

Put the value into the formula

\dfrac{1}{R}=\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}

\dfrac{1}{R}=\dfrac{1}{4}

R=4\ \Omega

We need to calculate the current in the circuit

Using ohm's law

V=IR

I=\dfrac{V}{R}

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I=\dfrac{10}{4}

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4 0
3 years ago
LINK OR PDF = REPORT
seraphim [82]

C

Explanation:

that's just what I learned in school

3 0
3 years ago
Read 2 more answers
A charge moves a distance of 1.8 cm in the direction of a uniform electric field having a magnitude of 214 N/C. The electrical p
Andrei [34K]

Answer:

 13.4 x 10 raise to power -19  C

Explanation:

. The distance moved by a charge in the direction of a uniform electric field is d= 1.8 cm =0.018 m

. The uniform electric field is  E = 214 N/M

, The decrease in electrical potential energy is   d(P.E) = 51.63 x 10 raise to power -19 J

Let the magnitude of the charge of the moving particle be q

which is given by the equation

d(P.E) =qEd

51.63 x 10 power -19 = q(214)(0.018)

51.63 x 10 power -19 =3.852q

by making q the formular,

q = 13.4 x 10 power -19 C  

5 0
3 years ago
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