Answer:
![v_s = 97.14 m/s](https://tex.z-dn.net/?f=v_s%20%3D%2097.14%20m%2Fs)
Explanation:
As per Doppler's effect of sound the frequency of the sound when source is approaching the observer is given as
![f_1 = f_o\frac{v}{v- v_s}](https://tex.z-dn.net/?f=f_1%20%3D%20f_o%5Cfrac%7Bv%7D%7Bv-%20v_s%7D)
similarly when source is moving away from the observer then its frequency is given as
![f_2 = f_o\frac{v}{v + v_s}](https://tex.z-dn.net/?f=f_2%20%3D%20f_o%5Cfrac%7Bv%7D%7Bv%20%2B%20v_s%7D)
now we know that the ratio of two frequency is
![\frac{f_1}{f_2} = 1.80](https://tex.z-dn.net/?f=%5Cfrac%7Bf_1%7D%7Bf_2%7D%20%3D%201.80)
![\frac{v + v_s}{v - v_s} = 1.80](https://tex.z-dn.net/?f=%5Cfrac%7Bv%20%2B%20v_s%7D%7Bv%20-%20v_s%7D%20%3D%201.80)
![v + v_s = 1.80 v - 1.80 v_s](https://tex.z-dn.net/?f=v%20%2B%20v_s%20%3D%201.80%20v%20-%201.80%20v_s)
![0.80 v = 2.80 v_s](https://tex.z-dn.net/?f=0.80%20v%20%3D%202.80%20v_s)
![v_s = \frac{0.80}{2.80}v](https://tex.z-dn.net/?f=v_s%20%3D%20%5Cfrac%7B0.80%7D%7B2.80%7Dv)
![v_s = \frac{0.80 \times 340}{2.80}](https://tex.z-dn.net/?f=v_s%20%3D%20%5Cfrac%7B0.80%20%5Ctimes%20340%7D%7B2.80%7D)
![v_s = 97.14 m/s](https://tex.z-dn.net/?f=v_s%20%3D%2097.14%20m%2Fs)
B, the light should be travelling out of the optically dense medium to the optically less dense medium.
were d to read "... is greater than the critical angle" I'd agree with it. But it doesn't read that way ...
Which leaves b as the only one which I think is true. Which I find a bit odd.
Out of interest, TIR is often used in piping light down optical fibres, among many other applications.
Answer:
This is to optimize storage and transport.
Explanation:
Answer:
2.1406 ×
m/sec
Explanation:
we know that energy is always conserved
so from the law of energy conservation
![qV=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=qV%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
here V is the potential difference
we know that mass of proton = 1.67×
kg
we have given speed =50000m/sec
so potential difference ![V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%201.67%5Ctimes%2010%5E%7B-27%7D50000%5E2%7D%7B1.6%5Ctimes%2010%5E%7B-19%7D%7D%3D13.045)
now mass of electron =9.11×![10^{-31}](https://tex.z-dn.net/?f=10%5E%7B-31%7D)
so for electron
![\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.11%5Ctimes%2010%5E%7B-31%7Dv%5E2%3D1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%2013.045%3D2.1406%5Ctimes%2010%5E6%20m%2Fsec)
so the velocity of electron will be 2.1406×
m/sec
Elephant is sexual, whiptail lizard, is asexual jellyfish is asexual, <span> Amoeba produce asexualy because of binary fission, a parrot reporduces sexualy,and a redwood tree reporduces asexualy. I hope im right</span>