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3 years ago

Nutritionists use the ______ to measure how much energy we get from foods.

Physics

2 answers:

jek_recluse [69]3 years ago

8 0

Nutritionists use the calories to measure how much energy we get from foods.

Natali [406]3 years ago

6 0

It is measured in calories

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1000 tiene 3 ceros cuantos lugares crees que se tenga que recorrer el punto decimal

Neporo4naja [7]

Answer:

Explanation:

Scientific notation is very useful for very large and small quantities, it is based on placing an integer and respecting the decimal figures multiplied by a factor so that the measurement is not altered.

in the example of this exercise we must run the decimal point

1000 = 1,000 103³

TRASLATE

La notación científica es muy útil para magnitudes muy grandes y pequeñas, se basa en colocar un entero y el respeto las cifras en decimales multiplicado por un factor para que no se altere la medida.

en el ejemplo de este ejercicio debemos corre la punto decimal

1000 = 1,000 10³

4 0

3 years ago

Which image illustrates reflection? A B с D

Masja [62]

Answer: I beleive A

Explanation:

8 0

3 years ago

Read 2 more answers

A circular area with a radius of 6.50 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle du

White raven [17]

Answer:

$a. \phi _B=3.0528\times10^-^3T\ m^2\\ \\b. \phi_B=1.83299\times10^-^3T\ m^2\\\\c.\phi_B=0$

Explanation:

#Consider a circular area of radius $R=2.98cm$ in the xy-plane at z=0. This means all the are vector points toward the +ve z-axis.

a. first, find the magnetic flux if the magnetic field has a magnitude of $B=0.23T$ and points toward the +ve z-axis. The angle between the magnetic field and the area is $\theta=0$ . Hence the magnetic flux:-

$\phi _B=\int {\bar B} . d\bar A \\=\int BdAcos(\theta)=BAcos(0)=BA\\\\=\pi R^2B=\pi(6.50\times10^-^3m)^2(0.230T)\\=3.0528\times10^-^3 T\ m^2$

Hence flux magnitude in $+z$ direction is $3.0528\times10^-^3T \ m^2$

b. We now find the magnetic flux when the field has a magnitude of B=0.230T and points at an angle of $\theta=53.1\textdegree$ from the $+z$ direction.

Magnetic flux is calculated as:

$\phi _B=\int\bar B \bar dA\\=\int BdAcos (\theta)=BAcos(0)=BA\\=\pi R^2B=\pi(6.50\times 10^-^2m)^2(0.230T)\\=1.83299\times 10^-^3 T \ m^2$

Hence the flux at an angle of $53.1\textdegree$ is $1.83299\times 10^-^3T \ m^2$

c. We now need to find the magnetic flux if the field has a magnitue of B=0.230T and points in the direction of +y-direction. As with the previous parts, the magnetic flux will be calculated as:

$\phi_B= \int\bar B \times d\bar A\\=\int BdAcos(\theta)\\=BAcos(90\textdegree)\\=0$

Hence the magnetic flux in the +y-direction is zero.

3 0

3 years ago

Hi please zoom in to see it clearly, uh you don’t have to answer them all but it would be nice !!! (no links please) :D

kap26 [50]

12.could be D
13.A
14.D
15.C
16.A

3 0

3 years ago

(b) The output current of the generator is 2.0A. The output potential difference (p.d.) of the

Luden [163]

Answer:

P = 22 watts

Explanation:

Given that,

The output power of the generator = 2 a

The output potential difference = 11 V

We need to find the output power of the generator. The formula for the output power is given by :

$P=V\times I\\\\P=11\times 2\\\\P=22\ W$

So, the output power of the generator is equal to 22 Watts.

8 0

3 years ago