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kotegsom [21]
3 years ago
5

3 If methane burns in a poor supply of air it will give carbon

Chemistry
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

2CH4 + 3O2 → 2CO + 4H2O

Explanation:

When methane is burnt in adequate supply of oxygen, then carbon dioxide is produced but when methane is burnt in limited supply of oxygen, then carbon mono-oxide is produced.

The balanced equation for the same is as follows -

2CH4 + 3O2 → 2CO + 4H2O

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A team of engineers is doing a cost-benefit analysis to determine whether
beks73 [17]

Answer:

1) The risk of high cost due to increased resource requirements

2) The risk of late entry into the (a changed) market

Explanation:

The analysis being performed by the engineers = A cost benefit analysis to determine if a new technology should be developed

A cost-benefit analysis is a process of appraising or measuring the advantages, benefits of a policy, action or decision, so as to find the (equilibrium) balance point between the costs of the decision or action

The risk to be considered are;

1) The risk of high cost due to increased resource requirements

The increased cost required for the development of the new technology now which due to the unlikely existence of a similar invention in the market that will give them an advantage of increased profits

2) The risk of late entry into the (a changed) market

The changes in the consumer preferences, market landscape, and the likely introduction into the market of a similar invention by the competition in the near future which will reduce the amount of profits that can be gained from the invention

3 0
3 years ago
Which is the strongest acid listed in the table?
andrew11 [14]

Answer:

Hydrofluoric acid.

Explanation:

To know which of the acid is the strongest, let us determine the pka of each acid. This is illustrated below:

1. Acetic acid

Ka = 1.8x10^-5

pKa =..?

pKa = –logKa

pKa = –Log 1.8x10^-5

pKa = 4.74

2. Benzoic acid

Ka = 6.5x10^-5

pKa =..?

pKa = –logKa

pKa = –Log 6.5x10^-5

pKa = 4.18

3. Hydrofluoric acid.

Ka = 6.8x10^-4

pKa =..?

pKa = –logKa

pKa = –Log 6.8x10^-4

pKa = 3.17

4. Hypochlorous acid

Ka = 3.0x10^-8

pKa =..?

pKa = –logKa

pKa = –Log 3.0x10^-8

pKa = 7.52

Note: the smaller the pKa value, the stronger the acid.

The pka of the various acids as calculated above is given below:

Acid >>>>>>>>>>>>>>>>>> pKa

1. Acetic acid >>>>>>>>>> 4.74

2. Benzoic acid >>>>>>>> 4.18

3. Hydrofluoric acid >>>> 3.17

4. Hypochlorous acid >> 7.52

From the above illustration, we can see that hydrofluoric acid has the lowest pKa value. Therefore, hydrofluoric acid is the strongest among them.

6 0
3 years ago
How are scientific questions answered?
galben [10]

Answer:

D

Explanation:

Scientists always perform tests and observe and measure in the physical world to prove their points or answer their questions.

3 0
3 years ago
49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. w
inna [77]

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The  value is  \epsilon  =  4118.1 \  M^{-1} cm^{-1}  

Explanation:

From the question we are told that

   The volume of the stock solution is  V_1   =  49.9 mL  =  0.0499 \  L  

   The concentration of the stock solution is  C_1  =  0.00292 \  M

   The volume of the diluted solution is  V_2 =  1.00 \  L

   The absorbance is  A =  0.600

Generally the from the titration equation we have that

         C_1 * V_1 =  C_2 * V_2

=>      0.00292  * 0.0499 =  C_2 * 1

=>     C_2 = 0.0001457 \  M

Generally from  Beer's law we have that

      A  =  \epsilon  * l  *  C_2

=>   \epsilon  =  \frac{A}{ l  *  C_2 }

Here  l is the length who value is  1 cm because the unit of  molar  absorptivity coefficient of the dye is M^{-1} *  cm^{-1}

So

            \epsilon  =  \frac{0.600}{ 1   * 0.0001457   }  

=>       \epsilon  =  4118.1 \  M^{-1} cm^{-1}  

4 0
2 years ago
Determine the number of moles present in 32.5 g aluminum chloride.
Artyom0805 [142]
The number of moles in 32.5g of aluminum chloride is approximately 0.250 moles.
3 0
3 years ago
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