Increasing the temperature of gas in a container that cannot expand is a way to _______. decrease the volume of the gas decrease
1 answer:
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Answer:
Kp = 1.41 x 10⁻⁶
Explanation:
We have the chemical equation:
2 A(g) + 3 B(g)⇌ C(g)
In which A and B are the reactants and C is the product. We calculate first the change in the number of moles of gas (Δn or dn):
dn= (sum moles products - sum moles reactants)
= (moles C - (moles A + moles B))
= (1 - (2+3))
= 1 - 5
= -4
We have also the following data:
Kc = 63.2
T= 81∘C + 273 = 354 K
R = 0.082 L.atm/K.mol (it is a constant)
Thus, we introduce the data in the mathematical expression for the relation between Kp and Kc:
= (0.082 L.atm/K.mol x 354 K)⁻⁴ = 1.41 x 10⁻⁶
Density is the ratio of mass to the volume.
The mathematical expression is given as:
Now, density of isooctane =
Volume =
Since, 1 gallon = 3.78 L
So, 3.8 gal =
=
As, 1 L = 1000 mL
Therefore, =
Volume in mL =
Put the values,
=
Hence, mass of 3.8 gal of the gasoline is .