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Usimov [2.4K]
3 years ago
14

Increasing the temperature of gas in a container that cannot expand is a way to _______. decrease the volume of the gas decrease

the volume of the gas increase the pressure of the gas increase the pressure of the gas decrease the pressure of the gas decrease the pressure of the gas increase the volume of the gas
Chemistry
1 answer:
alex41 [277]3 years ago
4 0

Answer:

Increase the pressure of the gas

Explanation:

According to the Pressure law, for a fixed mass of gas, at a constant volume (V), the pressure (P) is directly proportional to the absolute temperature (T).

From the kinetic molecular theory, gases are composed of particles which are in constant motion, colliding with themselves as well as with the walls of their container.

When the temperature of these gas molecules is increased, the molecules acquire more kinetic energy and the rate of collisions increases. Since the container cannot expand, the increase in pressure is due to the increase in collisions between the molecules of the gas as well as with the walls of their container.

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How do you write 3.40 x 10 to the eighth power in standard form?
solong [7]

Answer:

272

Explanation:

hope it helps i double checked the math :D

7 0
3 years ago
What are the products of the following combustion reaction?<br><br> 2C2H2(g) + 5O2(g) →
kakasveta [241]
A combustion reaction of an  will generally produce CO2 and H20 -- carbon dioxide and water and/or an oxide

looking at the combustion material C2H2, you know that the end products will be CO2 and H20, so the question is how much of each will you get

well, look at the total amount of carbon atoms, 2 C2, which means a total of 4 carbon atoms in this reaction, since only CO2 has carbon atoms, that means there must be 4 CO2 as an end product and 4 CO2 will use up 4 of 5 O2 molecule leaving only 1 O2 molecule for the H2 reaction.

now O2 has a total of 2 oxygen molecules whereas H20 has only a single oxygen molecule, hence the end product must have 2 H20

check that the H atoms balance out on both sides
4 0
3 years ago
Read 2 more answers
A serving of soup contains 5.0 g of fat, 20.0 g of carbohydrates, and 3.0 g of protein. Determine how many kilocalories (kcal) a
marta [7]

<u>Answer:</u> The amount of kilocalories contained in the given serving of soup is 0.137 kCal

<u>Explanation:</u>

<u>As per the USDA:</u>

Carbohydrates provide 4 calories per gram, protein provides 4 calories per gram, and fat provides 9 calories per gram.

We are given

Mass of fat in the soup serving = 5.0 g

Mass of carbohydrates in the soup serving = 20.0 g

Mass of protein in the soup serving = 3.0 g

Conversion factor used:  1 kCal = 1000 Cal

Applying unitary method:

  • <u>For Fat:</u>

1 gram of fat provides 9 calories

So, 5.0 gram of fat will provide = \frac{9}{1}\times 5.0=45Cal=0.045kCal

  • <u>For Carbohydrates:</u>

1 gram of carbohydrates provides 4 calories

So, 20.0 gram of carbohydrates will provide =\frac{4}{1}\times 20.0=80Cal=0.080kCal

  • <u>For Proteins:</u>

1 gram of proteins provides 4 calories

So, 3.0 gram of fat will provide = \frac{4}{1}\times 3=12Cal=0.012kCal

Total kilocalories per serving = [0.045 + 0.080 + 0.012] kCal = 0.137 kCal

Hence, the amount of kilocalories contained in the given serving of soup is 0.137 kCal

4 0
3 years ago
The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime
krok68 [10]

Answer: The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = 2.83\times 10^{-3}

a - x = amount left after decay process  = 3.06\times 10^{-4}

559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=3.96\times 10^{-3}min^{-1}

The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

6 0
3 years ago
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SOVA2 [1]

Answer:

rust is a substance formed on iron coated when it reacts with water and its miosture.

two general method are--

1.after u make any object of iron wet make it dry fast.

2. coat its surface with paint or apply grease, oil or varnish.

3.also by Rusting of iron can be prevented by galvanization.

4 0
4 years ago
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