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Answer:
Oxidation number of each atom in sodium hydrogen carbonate ( NaHCO3) are
Na = +1
H = +1
C = +4
O = -2
Explanation:
Let's pick the first atom
NaHCO3
find oxidation number of Na
Na + 1 +4 + 3(-2) = 0( because there is no charge)
Na + 5 - 6 = 0
Na = 6 -5
Na = +1
Always put the sign
Find the oxidation number of H in NaHCO3
+1 + H + 4 + 3(-2) = 0.
H + 1 + 4 + 3(-2) = 0
H + 5 -6 = 0
H = 6 -5
H = +1
Find the oxidation number of C In NaHCO3
+1 +1 +C + 3(-2) = 0
C + 1+1-6 = 0
C +2 - 6= 0
C = 6 -2
C = +4
Find the oxidation number of O in NaHCO3
+1 + 1 + 4 + 3(O) = 0
6 + 3 (O) = 0
3(O) = -6
Divide through by 3 to get O
3(O) / 3 = -6 / 3
O = -6/3
O = -2
Answer:
Empirical formula:
Fe₂O
Subscript of iron in empirical formula is 2.
Explanation:
Empirical formula:
It is the simplest formula that gives the smallest whole number ratio between the atoms of elements present in a compound.
Given data:
Mass of iron = 87.47 g
Mass of oxygen = 12.53 g
Empirical formula = ?
Solution:
Number of gram atoms of iron = 87.47 /55.845 =1.57 grams atoms
Number of gram atoms of oxygen = 12.53 / 16 = 0.78 grams atoms
Atomic ratio:
Fe : O
1.57/0.78 : 0.78/0.78
2 : 1
Fe : O = 2 : 1
Empirical formula:
Fe₂O
Subscript of iron in empirical formula is 2.
