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N76 [4]
2 years ago
9

The potential difference between two parallel plates is 227 V. If the plates are 6.8 mm apart, what is the electric field betwee

n them? O S.0x10 N/C O 28 x 10* N/C O 4.1 x 10 N/C O 3.3 x 10 N/C
Physics
1 answer:
nalin [4]2 years ago
3 0

Answer:

E=3.3\times 10^4N/C

Option D is the correct answer.

Explanation:

Electric field, E is the ratio of potential difference and distance between them.

Potential difference, V = 227 V

Distance between plates = 6.8 mm = 0.0068 m

Substituting,

         E=\frac{V}{d}=\frac{227}{0.0068}=3.3\times 10^4N/C

Option D is the correct answer.

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Answer:

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Explanation:

Given:

Wave velocity ( v ) = 330 m / sec

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We have to calculate Frequency ( f ):

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v = λ f

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Putting values here we get:

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