Question

The potential difference between two parallel plates is 227 V. If the plates are 6.8 mm apart, what is the electric field between them? O S.0x10 N/C O 28 x 10* N/C O 4.1 x 10 N/C O 3.3 x 10 N/C

Answer 1

Answer:

$E=3.3\times 10^4N/C$

Option D is the correct answer.

Explanation:

Electric field, E is the ratio of potential difference and distance between them.

Potential difference, V = 227 V

Distance between plates = 6.8 mm = 0.0068 m

Substituting,

         $E=\frac{V}{d}=\frac{227}{0.0068}=3.3\times 10^4N/C$

Option D is the correct answer.