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Pepsi [2]
3 years ago
10

_________________ states that when a stress is applied, a reversible reaction will undergo a shift in order to re-establish its

equilibrium.
LaChatelier's Principle

Boyle's Law

Avagadro's law

Charles Law
Chemistry
1 answer:
pochemuha3 years ago
5 0

LaChatelier's Principle

LaChatelier's Principle is a principle stating that if a constraint (such as a change in pressure, temperature, or concentration of a reactant) is applied to a system in equilibrium, the equilibrium will shift so as to tend to counteract the effect of the constraint.

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What substance can act as catalysts in the body?
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Answer:

Enzymes

Explanation:

Enzymes are proteins that can act as  catalysts in the body.

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What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?
kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of Al(OH)_3 = 0.610 g

Molar mass of Al(OH)_3 = 78 g/mol

\text{Number of moles}=\frac{0.610g}{78g/mol}

Number of moles of Al(OH)_3 = 0.0078 moles

The reaction between Al(OH)_3 and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

By Stoichiometry,

1 mole of  Al(OH)_3 reacts with 3 moles of HCl

So, 0.0078 moles of Al(OH)_3 will react with \frac{3}{1}\times 0.0078 = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

0.0234moles=\frac{\text{Given mass}}{36.5g/mol}

Mass of HCl required will be = 0.8541 grams

3 0
3 years ago
Determine the molar mass of barium sulfide, BaS
matrenka [14]

Answer: 169.39 g/mol

Explanation:

3 0
3 years ago
Initially, a particular sample has a total mass of 200 grams and contains 128 x 1010 radioactive nuclei. These radioactive nucle
lubasha [3.4K]

Explanation:

Formula to calculate how many particles are left is as follows.

              N = N_{0} (\frac{1}{2})^{l}

where,     N_{0} = number of initial particles

                              l = number of half lives

As it is given that number of initial particles is 128 \times 10^{10} and number of half-lives is 3.

Hence, putting the given values into the above equation as follows.

               N = N_{0} (\frac{1}{2})^{l}

                    = 128 \times 10^{10}(\frac{1}{2})^{3}

                    = 16 \times 10^{10}

or,                    1.6 \times 10^{11}

Thus, we can conclude that 1.6 \times 10^{11} particles of radioactive nuclei remain in the given sample.

In five hours we've gone through 5 half lives so the answer is:

particles

8 0
3 years ago
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