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3 years ago

Where do expect to find the most reactive metals on the periodic table;?

Chemistry

2 answers:

Rus_ich [418]3 years ago

7 0

Answer:

You can find the most reactive metals in the periodic table by looking for metals called alkali metals.

Explanation:

Alkali metals are chemical elements of group 1A of the periodic table with similar properties. The group consists of the following metals: lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs) and frâncio (Fr). They are low density metals, and moles. They are electropositive and highly reactive.

To know whether one metal is more reactive than another, it is important to remember the concept of electropositivity, that is, the ability of one atom to yield electrons to another atom during a bond. Thus, if one metal is more electropositive than another, it has a greater tendency to lose electrons in a bond and therefore tends to be more reactive.

faltersainse [42]3 years ago

5 0

The most reactive metals on the periodic table would have to be the alkali metals.
I hope this helps!
Have a nice day (:

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In compliance with conservation of energy, Einstein explained that in the photoelectric effect, the energy of a photon (hv) abso

3241004551 [841]

Answer:

a) 1.866 × 10 ⁻¹⁹ J b) 3.685 × 10⁻¹⁹ J

Explanation:

the constants involved are

h ( Planck constant) = 6.626 × 10⁻³⁴ m² kg/s

Me of electron = 9.109 × 10 ⁻³¹ kg

speed of light = 3.0 × 10 ⁸ m/s

a) the Ek ( kinetic energy of the dislodged electron) = 0.5 mu²

Ek = 0.5 × 9.109 × 10⁻³¹ × ( 6.40 × 10⁵ )² = 1.866 × 10 ⁻¹⁹ J

b) Φ ( minimum energy needed to dislodge the electron ) can be calculated by this formula

hv = Φ + Ek

where Ek = 1.866 × 10 ⁻¹⁹ J

v ( threshold frequency ) = c / λ where c is the speed of light and λ is the wavelength of light = 358.1 nm = 3.581 × 10⁻⁷ m

v = ( 3.0 × 10 ⁸ m/s ) / (3.581 × 10⁻⁷ m ) = 8.378 × 10¹⁴ s⁻¹

hv = 6.626 × 10⁻³⁴ m² kg/s × 8.378 × 10¹⁴ s⁻¹ = 5.551 × 10⁻¹⁹ J

5.551 × 10⁻¹⁹ J = 1.866 × 10 ⁻¹⁹ J + Φ

Φ = 5.551 × 10⁻¹⁹ J - 1.866 × 10 ⁻¹⁹ J = 3.685 × 10⁻¹⁹ J

7 0

3 years ago

In which situation is the object experiencing unbalanced forces?

olga2289 [7]

The moving car experiences unbalanced forces when applying brakes; when a car is slowing as it reaches a stop light.

<h3> Explanation: </h3>

When the car driver applies brakes to a car in order to stop, an unbalanced force is applied to the car. The speed of car gradually reduces and there’s a decrease in acceleration; a net force acts on it.

Options A and D has a box and a rocket always in a rest position. A car with cruise control is an adaptable speed setting for a vehicle which helps it to maintain a fairly constant speed. Constant velocity gives zero acceleration and hence no considerable unbalanced forces appear.

8 0

3 years ago

Read 2 more answers

What is the molar mass of magnesium tartrate

Leya [2.2K]

Answer:

172.385 g/mol

Explanation:

Magnesium Tartrate is C4H4MgO6

C - 12.01 g/mol

H - 1.01 g/mol

Mg - 24.305 g/mol

O - 16.00 g/mol

12.01(4) + 1.01(4) + 24.305 + 16(6) = 172.385 g/mol

3 0

3 years ago

Read 2 more answers

What are the number of protons, electrons, and neutrons in one atom of titanium?.

Olin [163]

Answer:

Protons: 22

Neutrons: 26
Electrons: 22

Explanation:

Titanium's atomic number is 22, meaning that the number of protons it has in its nucleus is also 22. # of electrons = # of protons, so the number of electrons is also 22. Titanium has an atomic mass of 47.867, but we can round up to 48. To find the atomic mass, we add up number of protons and neutrons. We know the number of protons as 22, so we subtract 22 from 48 and get a number of 26. Thus, the number of neutrons is 26.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0

2 years ago

SO2(g) + NO2(g) ↔ SO3(g) + NO(g) Kc = 0.33 A reaction mixture contains 0.41 M SO2, 0.14 M NO2, 0.12 M SO3 and 0.14 M NO. Which o

stepladder [879]

Answer:

The reaction will shift in the direction of products.

Explanation:

Step 1: Data given

A reaction mixture contains:

0.41 M SO2

0.14 M NO2

0.12 M SO3

0.14 M NO

Step 2: The balanced equation

O2(g) + NO2(g) ↔ SO3(g) + NO(g) Kc = 0.33

Step 3: Define the direction of the shift of reaction:

When Q<K, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.

When Q>K, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants.

When Q=K, the system is at equilibrium and there is no shift to either the left or the right.

Step 4: Calculate Q

Q = [NO][SO3]/[SO2][NO2]

Q = (0.14 *0.12)/(0.41*0.14)

Q = 0.0168/0.0574

Q = 0.293

Q<Kc

This means there are more reactants than products. Thud, some of the reactants will become products, causing the reaction to shift to the right.

The reaction will shift in the direction of products.

8 0

3 years ago