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STatiana [176]
3 years ago
5

As the temperature of a liquid solvent increases, the amount of solute that can dissolve in it ________. decreases remains const

ant increases decreases by 1º celsius for every milliliter of solvent
Chemistry
1 answer:
Nookie1986 [14]3 years ago
6 0
Answer:
              
<span>As the temperature of a liquid solvent increases, the amount of solute that can dissolve in it <u>increases</u>.

Explanation:
                    The solubility of most solutes in a solvent increases with increase in temperature. This solubility is closely related to the heat of solution, (the heat evolved or absorbed when solute is dissolved in solvent). Hence, majority of solutes when dissolved in solvent absorbs heat and makes the overall heat of solution positive. Hence, in this case more heat provided will increase the rate of solubility.</span>
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yawa3891 [41]

Given:

E = 7.3 × 10–17 Hz                                                                                      

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Now <em>E = hf</em>

where E is the energy of the photon                                                          

h is the Planck's constant                                                                          

f is the frequency of the photon

Substituting the values in the equation we get                                        

E= 7.3 × 10^-17 × 6.63 × 10^-34                                                                  

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4 years ago
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Answer:

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4 years ago
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Answer:

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Explanation:

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Reorder the terms:

13 + 11x = 12x + 6

Reorder the terms:

13 + 11x = 6 + 12x

Solving

13 + 11x = 6 + 12x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12x' to each side of the equation.

13 + 11x + -12x = 6 + 12x + -12x

Combine like terms: 11x + -12x = -1x

13 + -1x = 6 + 12x + -12x

Combine like terms: 12x + -12x = 0

13 + -1x = 6 + 0

13 + -1x = 6

Add '-13' to each side of the equation.

13 + -13 + -1x = 6 + -13

Combine like terms: 13 + -13 = 0

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Combine like terms: 6 + -13 = -7

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Divide each side by '-1'.

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kiruha [24]

Answer:

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