Answer:
the minimum records to be retrieved by using Chebysher - one sided inequality is 17.
Step-by-step explanation:
Let assume that n should represent the number of the students
SO,
can now be the sample mean of number of students in GPA's
To obtain n such that 
⇒ 
However ;

![E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D](https://tex.z-dn.net/?f=E%28x%5E2%29%20%3D%20D%5Cint%5Climits%5E4_2%20%282%2Be%5E%7B-x%7D%29dx%20%5C%5C%20%5C%5C%20%3D%20%5Cdfrac%7BD%7D%7B3%7D%5Be%5E%7B-4%7D%20%282e%5Ex%20x%5E3%20-3x%5E2%20-6x%20-6%29%5D%5E4__2%7D%7D%3D%2038.21%20%5C%20D)
Similarly;

⇒ 
⇒ 
⇒ 

∴ 
Now; 
Using Chebysher one sided inequality ; we have:

So; 
⇒ 
∴ 
To determine n; such that ;

⇒ 

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.
Answer: 0.49 ± 0.0237
Step-by-step explanation: A interval of a 99% confidence interval for the population proportion can be found by:
± z.
is the proportion:
= 
= 0.49
For a 99% confidence interval, z = 2.576:
0.49 ± 2.576.
0.49 ± 2.576.
0.49 ± 2.576.(0.0092)
0.49 ± 0.0237
For a <u>99% confidence interval</u>, the proportion will be between 0.4663 and 0.5137 or 0.49 ± 0.0237
It should be 34/5*. If you create an improper fraction out of the original one, then creating the reciprocal will be easier.
Answer:
b, c, d.
Step-by-step explanation: