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4 years ago

State a rule that describes how to predict the relative velocities of the two carts after the explosion.

Physics

1 answer:

kobusy [5.1K]4 years ago

5 0

Answer:

If this explosion is occurring in a closed environment this 'rule' would be:

The conservation of momentum.

Explanation:

In a close system which means the experiment is isolated from the surrounding environment and therefore not allowed to interact with its external space will have the same amount of momentum at the end of the experiment as the beginning by the equation of p=mv, p is momentum, m is mass and v is velocity.

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The electron structures of atoms are not involved in the emission of:

nekit [7.7K]

The correct one is gamma rays. Lets go over them one by one.

Gamma rays are rays that arise from gamma decay, a type of radioactive decay. Often, after another decay, the nucleus is still unstable and it gives off energy in the form of gamma rays to stabilize itself. Hence, gamma rays have nothing to do with the electron structure, only with the nucleus of the atom.

X-rays are the product of accelerating electrons, hence only specific atoms can emit a specific energy of X-rays; similarly for the photoelectric phenomenon, the energy which is needed for photoelectrons to be created depends on the electron structure of the atom (in both cases, it is important to see how strong the bond between electron and atom is).
Finally, spectral lines differ depending on the electron structure of the atoms since electrons with different energies absorb different frequencies of light.

7 0

3 years ago

Galileo was the first scientist to do which of the following?

MA_775_DIABLO [31]

He was the first to improve the telescope i believe

3 0

3 years ago

Read 2 more answers

If an object accelerates from rest, with a constant acceleration of 5.4 m/s2, what will its velocity be after 28s?

aleksklad [387]

Vf = Vi + at
Vf = 0 + 5.4•28
= 151.2m/s..
not sure if its right

6 0

3 years ago

A large airplane typically has three sets of wheels: one at the front and two farther back, one on each side under the wings. Co

Tems11 [23]

(a) The force the ground exerts on each set of rear wheels when the plane is at rest on the runway is 0.743 MN.

(b) The force the ground exerts on the front set of wheels is 0.239 MN.

<h3>Center mass of the airplane</h3>

The concept of center mass of an object can be used to dtermine the mass distribution of the airplane along the line through the center.

<h3>Some assumptions</h3>

The wheels under the wind do not pass through the center line.
The position of the front wheel is constant and it is zero mark (origin).
The rear wheels are at 21.7 m mark

Position of the center mass of the plane is calculated as follows;

Let the position of the center mass, Xcm = y

the center mass is 3 m in front of rear wheels, that is

21.7 - y = 3

y = 21.7 - 3

y = 18.7 m

Xcm = 18.7 m

<h3>Mass of the plane at the position of the rear wheels</h3>

Let the mass of the plane at front wheels = M1

Let the mass of the plane at rear wheels = M2

$X_{cm} = \frac{M_1x_1 + M_2x_2}{M_1 + M_2}$

$18.7 = \frac{M_1(0) + M_2(21.7)}{177000} \\\\3,309,900 = 21.7M_2\\\\M_2 = \frac{3,309,900}{21.7} \\\\M_2 = 152,529.95 \ kg$

<h3>Force exerted by the ground on each rear wheel</h3>

There are two rear wheels, and the force exerted on each wheel due to mass of the airplane at this position is calculated as follows;

$W = mg\\\\W_1 = W_2 = \frac{1}{2} (mg) = \frac{1}{2} (152,529.95 \times 9.8) = 743,396.76 \ N= 0.743 \ MN$

<h3>Mass of the plane at the position of the front wheel</h3>

M1 + M2 = 177,000

M1 = 177,000 - M2

M1 = 177,000 - 152,529.95

M1 = 24,470.05 kg

<h3>Force exerted by the ground on the front wheel</h3>

W = mg

W = 24,470.05 x 9.8

W = 239,806.5 N = 0.239 MN

Learn more about center mass here: brainly.com/question/13499822

7 0

2 years ago

A 12-V battery maintains an electric potential difference between two parallel metal plates separated by 10 cm. What is the elec

Sauron [17]

Answer:

The electric field between the plates is 120 V/m.

(c) is correct option.

Explanation:

Given that,

Potential difference = 12 volt

Distance = 10 cm = 0.1 m

We need to calculate the electric field between the plates

Using formula of electric field

$E = \dfrac{V}{d}$

Where, V = potential difference

d = distance between the plates

Put the formula

$E =\dfrac{12}{0.1}$

$E=120\ V/m$

Hence, The electric field between the plates is 120 V/m.

4 0

4 years ago