Answer:
First Question

Second Question
The wavelength is for an X-ray
Explanation:
From the question we are told that
The width of the wall is 
The first excited state is
The ground state is 
Gnerally the energy (in MeV) of the photon emitted when the proton undergoes a transition is mathematically represented as
![E = \frac{h^2 }{ 8 * m * l^2 [ n_1^2 - n_0 ^2 ] }](https://tex.z-dn.net/?f=E%20%20%20%3D%20%20%20%5Cfrac%7Bh%5E2%20%7D%7B%208%20%2A%20m%20%20%2A%20%20l%5E2%20%5B%20n_1%5E2%20-%20n_0%20%5E2%20%5D%20%7D)
Here h is the Planck's constant with value 
m is the mass of proton with value 
So
![E = \frac{( 6.626*10^{-34})^2 }{ 8 * (1.67 *10^{-27}) * (10 *10^{-15})^2 [ 2^2 - 1 ^2 ] }](https://tex.z-dn.net/?f=E%20%20%3D%20%20%20%5Cfrac%7B%28%206.626%2A10%5E%7B-34%7D%29%5E2%20%7D%7B%208%20%2A%20%281.67%20%2A10%5E%7B-27%7D%29%20%20%2A%20%20%2810%20%2A10%5E%7B-15%7D%29%5E2%20%5B%202%5E2%20-%201%20%5E2%20%5D%20%7D)
=> 
Generally the energy of the photon emitted is also mathematically represented as

=> 
=> 
=> 
Generally the range of wavelength of X-ray is 
So this wavelength is for an X-ray.
<span>The last main subatomic particle to be discovered was the
antihelium-4. It was discovered on 2011
and it is measured and produces through the STAR detector. The Antihelium-4 was discovered accidentally
when an experiment was conducted. It is
also the first particle that was discovered by the means of experiment.</span>
Im 99% sure
tan^-1 (6.2/22)= 15.7º
with 2 significant figures 16º
It would take about 2 thirds of a second or .66666666 repeating of a second. please give brainliest?