The current will decrease as the resistance has now increased, meaning less current will be 'let through' the resistor. (assuming it's in series, there's no image)
Answer:
4 m/s
Explanation:
m1 = m2 = m
u1 = 20 m/s, u2 = - 12 m/s
Let the speed of composite body is v after the collision.
Use the conservation of momentum
Momentum before collision = momentum after collision
m1 x u1 + m2 x u2 = (m1 + m2) x v
m x 20 - m x 12 = (m + m) x v
20 - 12 = 2 v
8 = 2 v
v = 4 m/s
Thus, the speed of teh composite body is 4 m/s.
Answer:
A. h = 2.15 m
B.
Pb' = 122 KPa
Explanation:
The computation is shown below:
a) Let us assume the depth be h
As we know that
After solving this,
h = 2.15 m
Therefore the depth of the fluid is 2.15 m
b)
Given that
height of the extra fluid is
h' = 0.355 m
Now let us assume the pressure at the bottom is Pb'
so, the equation would be
Pb' = 122 KPa
<em>mass (m)= 5 kg</em>
<em>height (h)= 9m </em>
<em>gravity (g)= 9.8 m/s^2</em>
It has Potential energy. (PE)
• PE = mgh
Replacing:
PE = 5 * 9.8 * 9 = 441 Joules
