Since g is constant, the force the escaping gas exerts on the rocket will be 10.4 N
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What is Escape Velocity ?</h3>
This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.
Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.
To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters
- Mass (m) of the rocket 0.25 Kg
- Initial velocity u = 15 m/s
- Final Velocity v = 40 m/s
- Gravitational field intensity g = 9.8N/kg
The force the gas exerts of the rocket = The force on the rocket
The rate change in momentum of the rocket = force applied
F = ma
F = m(v - u)/t
F = 0.25 x (40 - 15)/0.6
F = 0.25 x 41.667
F = 10.42 N
Since g is constant, the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.
Learn more about Escape Velocity here: brainly.com/question/13726115
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1) c. 2 m/s
Explanation:
The relationship between frequency, wavelength and speed of a wave is
where
v is the speed
is the wavelength
f is the frequency
For the wave in this problem,
f = 4 Hz
So, the speed is
2) a. 2.8 m/s
The speed of the wave on a string is given
where
T is the tension in the string
is the linear mass density
In this problem, we have:
(final tension in the rope, which is twice the initial tension)
--> mass density of the rope
Substituting into the formula, we find
A single line indicates a bond between 2 atoms .
