The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?
1 answer:
Answer:
P₁ = ⅔ P₀
Explanation:
For this exercise we can use the ideal gas equation
PV = n R T
let's write the equation for the initial point, where we will use the subscript o and the end with subscript 2
Suppose the temperature does not change in the process
P₀V₀ / n₀ = P₁V₁ / n₁
They tell us that
V₁ = V₀ / 2
n₁ = n₀ / 3
we substitute
P₀ = P₁
P₁ = ⅔ P₀
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Answer:
Work done = 13605.44
Explanation:
Data provided in the question:
For elongation of 2.1 cm (0.021 m) work done by the spring is 3.0 J
The relation between Energy (U) and the elongation (s) is given as:
U = ................(1)
where,
k is the spring constant
on substituting the valeus in the above equation, we get
3.0 =
or
k = 13605.44 N/m
now
for the elongation x = 2.1 + 4.1 = 6.2 cm = 0.062 m
using the equation 1, we have
U =
or
U = 26.149 J
Also,
Work done = change in energy
or
W = 26.149 - 3.0 = 23.149 J
Answer:
+7.0 m/s
Explanation:
Let's take rightward as positive direction.
So in this problem we have:
a = -2.5 m/s^2 acceleration due to the wind (negative because it is leftward)
t = 4 s time interval
v = -3.0 m/s is the final velocity (negative because it is leftward)
We can use the following equation:
v = u + at
Where u is the initial velocity
We want to find u, so if we rearrange the equation we find:
and the positive sign means the initial direction was rightward.