The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?
1 answer:
Answer:
P₁ = ⅔ P₀
Explanation:
For this exercise we can use the ideal gas equation
PV = n R T
let's write the equation for the initial point, where we will use the subscript o and the end with subscript 2
Suppose the temperature does not change in the process
P₀V₀ / n₀ = P₁V₁ / n₁
They tell us that
V₁ = V₀ / 2
n₁ = n₀ / 3
we substitute
P₀ = P₁
P₁ = ⅔ P₀
You might be interested in
Answer:
The inside Pressure of the tank is
Solution:
As per the question:
Volume of tank,
The capacity of tank,
Temperature, T' = = 299.8 K
Temperature, T = = 288.2 K
Now, from the eqn:
PV = nRT (1)
Volume of the gas in the container is constant.
V = V'
Similarly,
P'V' = n'RT' (2)
Also,
The amount of gas is double of the first case in the cylinder then:
n' = 2n
where
n and n' are the no. of moles
Now, from eqn (1) and (2):