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kykrilka [37]
3 years ago
7

The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?​

Physics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

     P₁ = ⅔ P₀

Explanation:

For this exercise we can use the ideal gas equation

         PV = n R T

let's write the equation for the initial point, where we will use the subscript o and the end with subscript 2

         

Suppose the temperature does not change in the process

        P₀V₀ / n₀ = P₁V₁ / n₁

They tell us that

      V₁ = V₀ / 2

       n₁ = n₀ / 3

 

we substitute

     P_o \frac{V_o}{n_o} = P_1 \frac{V_o}{2}  \frac{3}{n_o}  

        P₀ = \frac{3}{2}     P₁  

        P₁ = ⅔ P₀

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