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kykrilka [37]
3 years ago
7

The volume of the vessel is reduced twice,and the number of molecules is reduced three times.How the pressure will change gas?​

Physics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

     P₁ = ⅔ P₀

Explanation:

For this exercise we can use the ideal gas equation

         PV = n R T

let's write the equation for the initial point, where we will use the subscript o and the end with subscript 2

         

Suppose the temperature does not change in the process

        P₀V₀ / n₀ = P₁V₁ / n₁

They tell us that

      V₁ = V₀ / 2

       n₁ = n₀ / 3

 

we substitute

     P_o \frac{V_o}{n_o} = P_1 \frac{V_o}{2}  \frac{3}{n_o}  

        P₀ = \frac{3}{2}     P₁  

        P₁ = ⅔ P₀

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A cyclist and his bicycle have a combined mass of 88 kg and a combined
SpyIntel [72]

Answer:D

Explanation:

Mark brainly

5 0
3 years ago
What is the net force on a bag pulled down by gravity with a force of 18 newtons and pulled upward by a rope with a force of 18
VARVARA [1.3K]

Answer:

0 N.

Explanation:

Force: This can be defined as the product of mass and the acceleration of the body. The S.I unit of force is Newton (N).

The expression of net force when both force act in the different direction is given as

F' = W-F ........................ Equation 1

Where F' = Net force on the bag, W = gravitational force on the bag, F = Force acting upward on the bag

Given: W = 18 N, F = 18 N.

Substitute into equation 1

F' = 18-18

F' = 0 N.

Hence the net force = 0 N.

4 0
3 years ago
A pilot wishes to flt his planne to an airport north of his current location
Ann [662]

Answer:

Time = 2758.62 seconds

Explanation:

Given the following data;

Speed = 290 m/s

Distance = 800 km to meters = 800 * 1000 = 800000

To find the time;

Time = distance/speed

Time = 800000/290

Time = 2758.62 seconds

Therefore, it will take the pilot 2758.62 seconds to reach the airport.

6 0
3 years ago
if pete (mass =90.00kg) weighs himself and finds that he weighs 30.0 pounds, how far away from the earth is he?
Svet_ta [14]

Here we know that mass of the person is 90 kg

His weight is given as 30 lbf

so here we can convert it into Newton as we know that

1 lbf = 4.45 N

Now from above conversion

30 lbf = 30 \times 4.45 = 133.45 N

now we can use this to find the gravity at this height

mg = 133.45

90\times g = 133.45

g = 1.49 m/s^2

now we know that with height gravity varies as

g' = g(\frac{R}{R+H})^2

1.49 = 9.8(\frac{6.37\times 10^6}{6.37\times 10^6 + h})^2

h = 1.0 \times 10^7 m

so above is the height from the surface of earth

4 0
3 years ago
Find deacceleration An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When
earnstyle [38]

Answer:

The deceleration is  a = -0.7273 \ m/s^2  

Explanation:

From the question we are told that

  The distance of the car from the crossing is d = 360 \  m

   The speed is u  = 16 \  m/s

    The reaction time of the engineer is  t = 0.53 \ s

Generally the distance covered during the reaction time is  

      d_r = u * t

=>   d_r = 16 * 0.53

=>   d_r = 8.48 \ m

Generally distance of the car from the crossing after the  engineer reacts is

      D = d- d_r        

=> D = 360 - 8.48      

=> D = 352 \ m

Generally from kinematic equation

      v^2 = u^2 + 2as

Here v is the final velocity of the car which is  0 m/s

So

        0^2 = 16^2 + 2 * a * 352

=>    a = -0.7273 \ m/s^2  

3 0
3 years ago
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