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Elena L [17]
4 years ago
9

joe forgot his homework at home.he runs home to get it.he accelerates from 0 to 15m/s in 5 seconds,runs at 15m/s for 50 seconds,

and then slows down from 15m/s to a stop in 3 seconds.what is the acceleration
Physics
1 answer:
Fantom [35]4 years ago
7 0

15m/s is his running speed which is faster than the around 28mph limit for humans and he stops in 3 seconds with division he slows down at a rate of 5 meters per second which means he loses 5m/s velocity per second so 5meters per second per second

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Unpolarized light with intensity S is incident on a series of polarizing sheets. The first sheet has its transmission axis orien
jeka94

Answer:

Explanation:

Given

Initial Intensity of light is S

when an un-polarized light is Passed through a Polarizer then its intensity reduced to half.

When it is passed through a second Polarizer with its transmission axis \theat =45^{\circ}

S_1=S_0\cos ^2\theta

here S_0=\frac{S}{2}

S_1=\frac{S}{2}\times \frac{1}{(\sqrt{2})^2}

S_1=\frac{S}{4}

When it is passed through third Polarizer with its axis 90^{\circ} to first but \theta =45^{\circ} to second thus S_2

S_2=S_0\cos ^2\theta

S_2=\frac{S}{4}\times \frac{1}{2}

S_2=\frac{S}{8}

When middle sheet is absent then Final Intensity will be zero                    

3 0
3 years ago
The howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 8.9 km. Assume the
Airida [17]

Answer:

\frac{I}{I_0}=113.68

Explanation:

P = Acoustic power = 63 µW

r = Distance to the sound source = 210 m

Acoustic power

P=IA\\\Rightarrow I=\frac{P}{A}\\\Rightarrow I=\frac{63\times 10^{-6}}{4\times \pi \times 210^2}

Threshold intensity = I_0=1\times 10^{-12}\ W/m^2

Ratio

\frac{I}{I_0}=\frac{\frac{63\times 10^{-6}}{4\times \pi \times 210^2}}{1\times 10^{-12}}\\\Rightarrow \frac{I}{I_0}=113.68

Ratio of the acoustic intensity produced by the juvenile howler to the reference intensity is 113.68

6 0
3 years ago
An 80-N crate is pushed at constant speed for a distance of 5.0 m upward along a smooth inclined plane that makes an angle of 30
Mice21 [21]

The work done by the pushing force is 200 J; option B.

<h3>What is work done in an inclined plane?</h3>

The work done in an inclined plane is given by the formula below:

  • Work done = Force * distance

Force, F = mgsinθ + ma

where a = 0

Work done = 80 * 5 * sin 30°

Work done = 200 J

In conclusion, work done is the product of force and distance.

Learn more about work done at: brainly.com/question/10712853

#SPJ1

4 0
2 years ago
Which statement describes nuclear fission
Harlamova29_29 [7]

The Splitting of a nucleus

3 0
3 years ago
Read 2 more answers
An electron in a hydrogen atom undergoes a transition from the n = 3 level to the n = 6 level. To accomplish this, energy, in th
Harlamova29_29 [7]

Answer:1.816\times 10^{-19} J

Explanation:

Given

E=\frac{hc}{\lambda }

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where h=Planck constant

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E=2.18\times 10^{-18}(\frac{1}{3^2}-\frac{1}{6^2})

E=2.18\times 10^{-18}\times \frac{1}{12}

E=1.816\times 10^{-19} J

7 0
3 years ago
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