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3 years ago

When the angle of incidence equals the angle of reflection it is called the law of

Physics

2 answers:

BartSMP [9]3 years ago

8 0

The angle of incidence ALWAYS equals the angle of reflection.

THAT'S the law of reflection.

Reptile [31]3 years ago

6 0

The law of reflection

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An Amtrak going 250m/s comes to a stop in 12s. What is the<br> acceleration?

astraxan [27]

Answer:

$a=\frac{v-u}{t} \\a = \frac{0-250}{12} = -20.83 m/s$

Explanation:

you mean deceleration right ? because the acceleration is 250m/s

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3 years ago

The temperature of an air parcel and the kinetic energy of an air parcel are ___________ related. this means that as the tempera

torisob [31]

The temperature of an air parcel and the kinetic energy of an air parcel are directly related. this means that as the temperature of the air parcel increases, the kinetic energy increases.

<h3>What is temperature?</h3>

Temperature is the measure of degree of hotness or coldness of a body.

Temperature is also the measure of the average kinetic energy of a system.

When the heat is applied to body, its temperature increases as the body gains heat.

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2 years ago

high school physics, no need detail explain, just give the answer, but you have to make sure thank you

Goshia [24]

Answer:many questions add point

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3 years ago

A man runs at an average speed of 5.0m/s how long will it take him to run 5.2km on a perfectly straight line

Anni [7]

The time taken is 1040 s.

<h3>What is speed?</h3>

The term speed refers to the rate at which the distance changes per unit time. This is why we define speed as the ratio of the distance to time for a body that is moving along a straight line.

Now;

We must first convert the distance to meters;

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1 year ago

You have an incident ray from a medium with a n1=1, through a medium with a n2 =3.325. If the incident angle is equal to 0.478 r

sesenic [268]

Answer:

0.139 rad

Explanation:

We use Snell's law $n_1sin\theta_1=n_2sin\theta_2$ , where if $n_1$ is the <em>refractive index</em> of the medium containing the <em>incident ray</em>, $\theta_1$ would be the <em>incident angle</em>, and if $n_2$ is the <em>refractive index</em> of the medium containing the <em>refracted ray</em>, $\theta_2$ would be the <em>refraction angle</em>, which we want, so we do: