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Tom [10]
2 years ago
5

Listed following are three possible models for the long-term expansion (and possible contraction) of the universe in the absence

of dark energy. Rank each model from left to right based on the ratio of its actual mass density to the critical density, from smallest ratio (mass density much smaller than critical density) to largest ratio (mass density much greater than critical density).1. coasting universe2. recollapsing universe3. critical universe
Physics
1 answer:
vazorg [7]2 years ago
8 0

Answer:

do your best

Explanation:

<u>babyboiiii∛√</u>

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A playground slide is inclined 40°. If a boy with a mass of 32 kg slides down for -3meters. How much work is done by gravity on
telo118 [61]

Answer:

the work done by gravity on the boy is 604.62 J

Explanation:

Given;

distance the boy slides, d = 3 m

angle of inclination of the playground, θ = 40⁰

mass of the boy, m = 32 kg

The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.

The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.

sin \theta = \frac{opposite }{hypotenuse} \\\\sin \theta = \frac{h}{d} \\\\h = dsin\theta\\\\h = 3 \times sin(40^0)\\\\h = 1.928 \ m

The work done by gravity on the boy is calculated as;

W = P.E = mgh

             = 32kg x 9.8m/s² x 1.928m

             = 604.62 J

Therefore, the work done by gravity on the boy is 604.62 J

8 0
3 years ago
Between 1911 and 1990, the top of the leaning bell tower at Pisa, Italy, moved toward the south at an average rate of 1.2 mm/y.T
Anit [1.1K]

Answer:

Angular speed, \omega=6.90\times 10^{-13}\ rad/s

Explanation:

It is given that,    

The top of the leaning bell tower at Pisa, Italy, moved toward the south at an average rate of, v = 1.2 mm/yr

1\ mm/yr=3.171\times 10^{-11}\ m/s

Velocity, v=3.80\times 10^{-11}\ m/s

Height of the tower, h = 55 m

The height of the tower is equivalent to the radius. Let \omega is the angular speed of the tower’s top about its base. The relation between the angular speed and the angular speed is given by :

v=r\omega

\omega=\dfrac{v}{r}

\omega=\dfrac{3.80\times 10^{-11}\ m/s}{55\ m}

\omega=6.90\times 10^{-13}\ rad/s

So, the average angular speed of the tower’s top about its base is 6.90\times 10^{-13}\ rad/s. Hence, this is the required solution.

6 0
3 years ago
What are the effects of radiation on different surfaces such as an ice- covered lake, a forest, an ocean, or an asphalt road?
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it could kill the fish in water

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0.75 km expressed in centimeters
Rufina [12.5K]
0.75 kilometer= 75000 centimeters
6 0
3 years ago
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What are the factors that keep a satellite in orbit
Ber [7]
They are the same factors that keep planets, asteroids, and comets in orbit. The factors are gravity.
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