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Tom [10]
3 years ago
5

Listed following are three possible models for the long-term expansion (and possible contraction) of the universe in the absence

of dark energy. Rank each model from left to right based on the ratio of its actual mass density to the critical density, from smallest ratio (mass density much smaller than critical density) to largest ratio (mass density much greater than critical density).1. coasting universe2. recollapsing universe3. critical universe
Physics
1 answer:
vazorg [7]3 years ago
8 0

Answer:

do your best

Explanation:

<u>babyboiiii∛√</u>

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The organism shown above belongs to A. the plant kingdom. B. both the animal kingdom and the protist kingdom. C. the animal king
Bumek [7]

The organism shown above belongs to "the animal kingdom".

<u>Answer:</u> Option C

<u>Explanation:</u>

The biological classification's hierarchy involves eight important taxonomic ranks. They are written below in decreasing order: Life > Domain > Kingdom > Phylum > Class > Order > Family > Genus > Species.

The U.S and Canada have historically used a six-kingdom scheme in their traditional textbook, such as Plantae, Animalia, Protista, Fungi, Archaea / Archaebacteria, and Bacteria / Eubacteria. The given image depicts snake which come under "Animalia Kingdom", carnivorous reptiles to  suborder Serpentes.

6 0
3 years ago
Read 2 more answers
One end of a piano wire is wrapped around a cylindrical tuning peg and the other end is fixed in place. The tuning peg is turned
liq [111]

Answer:

T = 3183 N

Explanation:

When the screw is turned by two turns then change in the length of the wire is given as

\Delta L = 2(2\pi r)

\Delta L = 4\pi r

\Delta L = 4(\pi)(1.0 mm)

\Delta L = 12.56 mm

now we know by the formula of Young's modulus

Y = \frac{T/A}{\Delta L/L}

so we have

T = \frac{AY \Delta L}{L}

T = \frac{\pi (0.55 \times 10^{-3})^2(2.0 \times 10^{11})(12.56 \times 10^{-3})}{0.75}

T = 3183 N

3 0
3 years ago
What is an amorphous solid?
Airida [17]
an amorphous solid is a solid that lacks the long-range order
7 0
3 years ago
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
frutty [35]

Answer:

Velocity=1.1m/s

Amplitude=0.35m

Explanation:

Given:

time 't' = 2.9s

wavelength 'λ'= 5.5m

distance 'd'=0.7m

The time period 't' is the time b/w two successive waves. Therefore, the time it takes from the boat to travel  from its highest point to its lowest is a half period.

So, T = 2 x 2.9 => 5.8 s

As we know that frequency is the reciprocal of time period, we have

f= 1/T = 1/5.8 =>0.2 Hz

In order to find how fast are the waves traveling, the velocity is given by

Velocity = f λ

V= 0.2 x 5.5 =>1.1m/s

The distance between the boat's highest point to its lowest point is double the amplitude.

Therefore , we can write

Amplitude 'A'= d/2 =>0.7/2 =>0.35m

8 0
3 years ago
Ice has a specific heat of 2090 J/(kg C) and water has a specific heat of 4186 J/(kg C). Water has a latent heat of fusion of 3.
zepelin [54]

Answer:

3.1 × 10⁷ J

Explanation:

The total heat required is the sum of the heats required in each stage.

1) Solid: from -60°C to 0°C.

Q₁ = c(s) × m × ΔT = (2090 J/kg.°C) × 10 kg × (0°C - (-60°C)) = 1.3 × 10⁶ J

where,

c(s): specific heat of the solid

m: mass

ΔT: change in the temperature

2) Solid to liquid at 0°C

Q₂ = Qf × m = (3.3 × 10⁵ J/kg) × 10 kg = 3.3 × 10⁶ J

where,

Qf: latent heat of fusion

3) Liquid: from 0°C to 100°C

Q₃ = c(l) × m × ΔT = (4186J/kg.°C) × 10 kg × (100°C - 0°C) = 4.2 × 10⁶ J

where,

c(l): specific heat of the liquid

4) Liquid to gas at 100 °C

Q₄ = Qv × m = (2.26 × 10⁶ J/kg) × 10 kg = 2.26 × 10⁷ J

where,

Qv: latent heat of vaporization

Total heat

Q₁ + Q₂ + Q₃ + Q₄

1.3 × 10⁶ J + 3.3 × 10⁶ J + 4.2 × 10⁶ J + 2.26 × 10⁷ J = 3.1 × 10⁷ J

3 0
3 years ago
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