Answer:
395 mg of Cl are in 3.44 g of CaCl₂
Explanation:
18.0 wt% CaCl₂ means that 18 g of salt, are contained in 100 g of solvent (assuming solvent as solution).
Let's apply a rule of three:
In 100 g of solution we have 18 g of salt
In 3.44 g of solvent we have (3.44 .18)/ 100 = 0.1692 grams of salt.
Now, let's convert this mass into moles (mass / molar mass)
0.1692 mass / 110.98 g/m = 0.00558 moles
1 mol of CaCl₂ has 1 mol of Ca and 2 moles of Cl
Then, 0.00558 moles of CaCl₂, would have the double of moles of Cl
0.00558 m .2 = 0.01116 moles of Cl.
Let's convert the moles into mass (mol . molar mass)
0.01116 moles of Cl . 35.453g/m = 0.395 grams of Cl.
Finally we convert grams to mg (x1000)
0.395 g = 395 mg
