Question

9. What is the total number of grams of NaOH (formula mass = 40.) needed to make 1.0 liter of a 0.20 M solution?

Answer 1

Answer:

8 gram

Explanation:

in case of NaOH, normality=molarity

so normality=molarity×acidity or basicity(in case of NaOH it's 1)

then

weight of NaOH required = volume in ml × equivalent weight × normality / 1000

so

1000× 40× 0.2/1000

=8 gram