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shusha [124]
3 years ago
5

In an exothermic reaction, the energy of the reactants is greater than the energy of

Chemistry
1 answer:
mojhsa [17]3 years ago
6 0

Answer:

H

Explanation:

If the energy content in the reactants is higher than the products, that means that the reaction must be giving away energy. So, in other words, chemical energy from the reactants must be released as heat.

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The energy that is transferred due to a temperature difference
Luden [163]
<span>The energy that is transferred due to a temperature difference is called heat. </span>
8 0
3 years ago
How many moles of iron (Fe) will be produced from 6.20 moles of carbon monoxide (CO) reacting with excess iron (III) oxide (Fe2O
bonufazy [111]

Answer:

4.13 moles of Fe

Explanation:

Step 1: Write the balanced equation

3 CO + Fe₂O₃ ⇒ 2 Fe + 3 CO₂

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of CO to Fe is 3:2.

Step 3: Calculate the moles of Fe formed from 6.20 moles of CO

We will use the previously established molar ratio.

6.20 mol CO × 2 mol Fe/3 mol CO = 4.13 mol Fe

8 0
3 years ago
Perform the following conversions:
ololo11 [35]

Answer:

a) 20^0C and 293K

b) 437K and 327.2^0F

c) -273^0C and 459.44^0F

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like ^0C , ^0Fand K  

These units of temperature are inter convertible.

t^0C=(t+273)K

t^oC=\frac{5}{9}\times (t^oF-32)

K-273=\frac{5}{9}\times (^oF-32)

a)  68°F (a pleasant spring day) to °C and K.

Converting this unit of temperature into ^0C and K by using conversion factor:

t^oC=\frac{5}{9}\times (68^oF-32)

t=20^0C

20^0C=(20+273)K=293K

b) 164°C (the boiling point of methane, the main component of natural gas) to K and °F

Conversion from degree Celsius to Kelvins  and Fahrenheit

164C=\frac{5}{9}\times (t^oF-32)

t^0F=327.2

164°C=(164+273)K=437 K

c) 0K (absolute zero, theoretically the coldest possible temperature) to °C and °F.

K-273=\frac{5}{9}\times (t^oF-32)

0-273=\frac{5}{9}\times (t^oF-32)

t=-459.4^0F

t^K=(0-273)^0C=-273^0C

8 0
3 years ago
A compound with an empirical formula of CH2O has a molar
NeTakaya

Answer:

c2h4o2

Explanation:

I am using my cell. This could take a bit

The Empical formula has a mass of

C 12

2H 2

O 16

total = 30

The molecular mass is given as 60 which is 2 times the empirical mass. Therefore multiply each element by 2 in the empirical formula.

You get C2H4O2

5 0
3 years ago
Drag each label to the correct location on the image identify the parts of the energy diagram
diamong [38]
If you would’ve attached a picture I’m sure it would’ve been a lot easier.
4 0
3 years ago
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