Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.
Answer:
Wet deposition
Explanation:
when the chemicals produced in the Earth can evaporate and reach the clouds, it will mixed with the water inside the clouds and form a slightly acid water than when is time to deposit the water into the Earth as snow, rain, fog or mist, the chemicals will travel with the water dissolved in it.
When they reach the soil, eventually, the water will evaporate or will be absorbed by soil, so the chemicals that are left behind, will reach the surface of Earth.
Depending where the chemicals were deposit, they can contaminate the sea, or other water bodies, or soil areas of crops, buildings, etc.
Hope this info is useful.
I think its A.
if one force cannot overcome the other, the object remains stationary.
Answer:
Condensation 212F or 100C, Freezing 32F or 0C
Explanation:
Condensation 212 degrees Fahrenheit or 100 degrees Celsius.
Freezing point 32 degrees Fahrenheit or 0 degrees Celsius.
