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Nastasia [14]
2 years ago
11

Explain, in terms of electronegativity difference, why the bond in a molecule of HF is more polar than the bond in a molecule of

HI.
Chemistry
2 answers:
padilas [110]2 years ago
4 0

Answer:

Explanation:

Electronegativity is defined as the ability of an element to attract electrons that link it to another element.

The covalent bond (chemical bond between atoms where electrons are shared, forming a molecule. This bond is established between non-metallic elements) between two atoms can be polar or nonpolar.

When two atoms have different electronegativities, the one with the highest electronegativity will attract the electrons towards each other, generating a separation between the positive and negative charges. In this way a polar bond is produced, the polarity of which will be as the electronegativity difference between the bonded atoms is greater.

In this case you know the following electronegativities:

  • H=2.1
  • F=4.0
  • I=2.5

So the electronegativity differences in the HI and HCl compounds are:

  • HF =4.0 - 2.1= 1.9
  • HI = 2.5 - 2.1= 0.4

Both compounds have element H that is part of it, only differing in F and I. Since F has greater electronegativity than I, the difference in electronegativity in compound HF will be greater. Then the HF compound will be more polar.

dem82 [27]2 years ago
3 0
Omg its a lol no more 2 explain lol That ez shizkubob
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Answer:

Explanation:

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pH = pka + log₁₀ \frac{[A^-]}{[HA]}

Where HA is the acid concentration and A⁻ is the conjugate base concentration.

The equilibrium of acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka: 4,75

Where <em>CH₃COOH </em>is the acid and <em>CH₃COO⁻ </em>is the conjugate base.

Thus, Henderson-Hasselbalch formula for acetic acid equilibrium is:

pH = 4,75 + log₁₀ \frac{[CH_{3}COO^-]}{[CH_{3}COOH]}

a) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[2 mol]}

<em>pH = 4,75</em>

<em></em>

b) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[1mol]}

<em>pH = 5,05</em>

<em></em>

I hope it helps!

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