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Nastasia [14]
3 years ago
11

Explain, in terms of electronegativity difference, why the bond in a molecule of HF is more polar than the bond in a molecule of

HI.
Chemistry
2 answers:
padilas [110]3 years ago
4 0

Answer:

Explanation:

Electronegativity is defined as the ability of an element to attract electrons that link it to another element.

The covalent bond (chemical bond between atoms where electrons are shared, forming a molecule. This bond is established between non-metallic elements) between two atoms can be polar or nonpolar.

When two atoms have different electronegativities, the one with the highest electronegativity will attract the electrons towards each other, generating a separation between the positive and negative charges. In this way a polar bond is produced, the polarity of which will be as the electronegativity difference between the bonded atoms is greater.

In this case you know the following electronegativities:

  • H=2.1
  • F=4.0
  • I=2.5

So the electronegativity differences in the HI and HCl compounds are:

  • HF =4.0 - 2.1= 1.9
  • HI = 2.5 - 2.1= 0.4

Both compounds have element H that is part of it, only differing in F and I. Since F has greater electronegativity than I, the difference in electronegativity in compound HF will be greater. Then the HF compound will be more polar.

dem82 [27]3 years ago
3 0
Omg its a lol no more 2 explain lol That ez shizkubob
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Determine the volume of hydrogen collected at STP and SATP, and the molar volume at STP and SATP
mario62 [17]
The other given data are: 
<span>Room temperature (°C) 22.0; pressure (kPa) 100.5; Water vapor pressure at 22 °C (2.60 kPa); Mass of Mg ribbon (0.05g);  Volume of hydrogen gas (mL) 48.3
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<span>Vstp = 22.4 L/mol, and Vsatp = 24.8 L/mol Vstp:0 degrees Celsius and 101.325 kPa while Vsatp: 25 degrees Celsius and 100 kPa. 100.5 kPa x 760 mm Hg/101.325 kP = 753.8119911 mmHg
 
</span><span>2HCl(g) + Mg(s) -> H2(g) + MgCl2(aq) nMg = 0.0020571899 mol nH2 = 0.0020571899 mol Wet H2 pressure = 100.5 kPa Dry H2 pressure = 97.9 kPa
</span><span>
So to determine the volume of hydrogen gas collected at STP: V2 = (753.8119911 mmHg)(48.3 mL)(273 K) / (295 K)(760 mmHg) = 44.33403003 mL.
</span>
<span>Molar volume at STP: mol/L = 44.33403003 mL / 0.0020571899 mol
= 21550.77176 mL/mol
= 21.55077176 L/mol
To determine volume of hydrogen gas collected at SATP:
V2 = (100.5 kPa)(48.3 mL)(298 K) / (295K)(100kPa) = 49.03514237 mL

Molar volume at SATP: mol/L = 49.03514237 mL / 0.0020571899 mol
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= 23.8359824 L/mol</span>
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3 years ago
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