Answer:
C
Step-by-step explanation:
The volume of the regular pyramid is ![V=\dfrac{1}{3}A_{base}H.](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7DA_%7Bbase%7DH.)
The base of given pyramid is regular hexagon with side 12 cm. The are of this hexagon consistsof area of 6 equilateral triangles and is equal to
![A_{base}=6\cdot \dfrac{1}{2}\cdot 12\cdot 10.4=374.4\ cm^2.](https://tex.z-dn.net/?f=A_%7Bbase%7D%3D6%5Ccdot%20%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%2012%5Ccdot%2010.4%3D374.4%5C%20cm%5E2.)
Hence, the volume of the pyramid is
![V=\dfrac{1}{3}\cdot 374.4\cdot 36=4,492.8\ cm^3.](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%5Ccdot%20374.4%5Ccdot%2036%3D4%2C492.8%5C%20cm%5E3.)
Answer:
80
Step-by-step explanation:
If Line PQ is parallel to Line SR, and Line PS is parallel to QR, we know that the two opposite angles would be congruent. Therefore, Angle R is equivalent to Angle P.
Angle R is 80 + D. D is unessential at the moment, seeing as 80 is the needed value for A.
G is between F and H.If GH=6 and FG=8x+2, and FH=16, find FG
please repost your question with more detail
Replace x^2+y^2 with r^2. Also replace y with r*sin theta.
Then we have r^2 = r*sin theta.
this can be reduced to r = sin theta.