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2 years ago

How many particles are in 3 moles?

1 answer:

3 0

We know that 1 mol= 6.02*10^23 particles.

3 mol* (6.02*10^23 particles/ 1 mol)= 1.81*10^24 particles.

The final answer is 1.81*10^24 particles~

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2.714 mole of helium has a mass of ______ grams.<br><br> (Enter just the number for this one.)

kifflom [539]

Hello!

To find the mass of helium, we need to multiply the total moles by the mass of helium. We are given 2.714 moles of helium, and the mass of helium is about 4.00 grams. Now, we multiply the two values together to get the grams.

2.714 moles x 4.00 grams = 10.856 grams

According to the number of significant figures, 2.714 moles of helium has a mass of 10.9 grams (exact value: 10.856 grams).

6 0

3 years ago

an engineering team is conducting a trial launch of a few rocket . which part is the engineering process is the team in ?

brilliants [131]

Answer:

Evaluate the result (Apex)

Explanation:

7 0

3 years ago

A car with a mass of 1500 kg is moving at a rate of 4 m s . Determine its kinetic energy

rodikova [14]

the correct answer is b) 12000 J

4 0

3 years ago

Read 2 more answers

Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)2(aq)+2

Setler79 [48]

Answer:

a) volume of ammonium iodide required =349 mL

b) the moles of lead iodide formed = 0.0436 mol

Explanation:

The reaction is:

$Pb(NO_{3})_{2}+2NH_{4}I -->PbI_{2}+2NH_{4}NO_{3}$

It shows that one mole of lead nitrate will react with two moles of ammonium iodide to give one mole of lead iodide.

Let us calculate the moles of lead nitrate taken in the solution.

Moles=molarityX volume (L)

Moles of lead nitrate = 0.360 X 0.121 =0.0436 mol

the moles of ammonium iodide required = 2 X0.0436 = 0.0872 mol

The volume of ammonium iodide required will be:

$volume=\frac{moles}{molarity}=\frac{0.0872}{0.250}=0.349L=349mL$

the moles of lead iodide formed = moles of lead nitrate taken = 0.0436 mol

7 0

3 years ago

a vehicle accelerates with 0.4 m/s. calculate tue time taken by the vehicle to increase its speed from 20m/s to 40m/s.

Grace [21]

Answer:

$\huge\boxed{\sf t = 50 \ seconds}$

Explanation:

<h3><u>Given data:</u></h3>

Acceleration = a = 0.4 m/s²

Initial Speed = $V_i$ = 20 m/s

Final Speed = $V_f$ = 40 m/s

<h3><u>Required:</u></h3>

Time = t = ?

<h3><u>Formula:</u></h3>

$\displaystyle a =\frac{V_f-V_i}{t}$

<h3><u>Solution:</u></h3>

Rearranging formula for t

$\displaystyle t =\frac{V_f-V_i}{a} \\\\t = \frac{40-20}{0.4} \\\\t = \frac{20}{0.4} \\\\\boxed{t = 50 \ seconds}\\\\\rule[225]{225}{2}$

6 0

2 years ago

Read 2 more answers