The structure of Dimethyl sulfide is H3C-S-CH3. It is produced naturally by some marine algae.
<u>Explanation:</u>
- DMS or dimethyl sulfide is formed by using two methyl groups combined with one sulfur atom. It is an organosulphur compound with a structural formula H3C-S-CH3.
- Most abundant biological sulfur compounds emitted to air and oceans by phytoplankton.
- DMS is produced naturally by the waste of dimethyl sulphoxide which is disposed into the sewer causing environmental odor problems.
- It is a flammable liquid that boils at 37 degrees celsius and a disagreeable smell produced from the cooking of certain vegetables also indicates bacterial contamination in the production of malt and brewing.
<h3>
Answer:</h3>
5.00 mol O₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.<u>
</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.01 × 10²⁴ atoms O₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
4.99834 mol O₂ ≈ 5.00 mol O₂
Answer:
CH₄
Explanation:
CH₃OH has hydrogen bonding due to the OH group present
NH₃ also has hydrogen bonding due to the NH bonds
H₂S has dipole-dipole forces present due to the polar SH bonds
HCl also has dipole-dipole forces due to the polar HCl bond
Answer:
The final volume will be 5.80 L
Explanation:
Step 1: Data given
Number of moles gas = 0.140 moles
Volume of gas = 2.78 L
Number of moles added = 0.152 moles
Step 2: Calculate the final volume
V1/n1 = V2/n2
⇒ with V1 = the initial volume = 2.78 L
⇒ with n1 = the initial number of moles = 0.140 moles
⇒ with V2 = The new volume = TO BE DETERMINED
⇒ with n2 = the new number of moles = 0.140 + 0.152 = 0.292 moles
2.78/0.140 = V2 /0.292
V2 = 5.80 L
The final volume will be 5.80 L