Non-ferromagnetic materials tend to have ______ electrons in each orbital

Chemistry

2 answers:

Fittoniya [83]3 years ago

6 0

Answer:

Non-ferromagnetic materials tend to have paired electrons in each orbital.

Explanation:

The non ferromagnetic materials have all paired electrons in each orbital, or a small number of unpaired electrons.

This can be justified given that the pairing of electrons with opisite spins (one with -1/2 and the other with +1/2) counteracts the magnetic properties that the element could have.

Sveta_85 [38]3 years ago

4 0

Non-ferromagnetic materials tend to have paired electrons in each orbital or very less unpaired electrons.

Example - Neon, its atomic number is 10 and all the electrons are pared. Now, Aluminum. Its atomic number is 13 with the electronic configuration 3 $p^{1}$ i.e. only one unpaired electron in the p- orbital. Now, consider iron its atomic number is 26 and its configuration is 3 $d^{6}$ . It has more number of unpaired electrons. Thus, neon is non-magnetic, aluminum is also non-magnetic but iron is magnetic.

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Answer: 1. C. polar covalent: electrons shared between silicon and sulfur but attracted more to the sulfur

2. B) $NH_3$

3. B) Fluorine

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1. A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.

Electronegativity difference = electronegativity of sulphur- electronegativity of silicon = 2.5 -1.8 = 0.7

Thus as electronegativity difference is less than 1.7 , the cond is polar covalent and as electronegativity of sulphur is more , the electrons will be more towards sulphur.

2. A molecular compound is usually composed of two or more nonmetal elements. Example: $NH_3$

Ionic compound is formed by the transfer of electrons from metals to non metals. Example: $Mg_3N_2$ , $AlCl_3$ and $LiBr$

3. For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here K is having an oxidation state of +1 and as the compound formed is KZ, the oxidation state of non metallic element Z should be -1. Thus the element Z is flourine which exists as diatomic gas $F_2$