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nalin [4]
3 years ago
8

Non-ferromagnetic materials tend to have ______ electrons in each orbital

Chemistry
2 answers:
Fittoniya [83]3 years ago
6 0

Answer:

Non-ferromagnetic materials tend to have <em>paired</em> electrons in each orbital.

Explanation:

The non ferromagnetic materials have all paired electrons in each orbital, or a small number of unpaired electrons.

This can be justified given that the pairing of electrons with opisite spins (one with -1/2 and the other with +1/2)  counteracts the magnetic properties that the element could have.

Sveta_85 [38]3 years ago
4 0
<span>Non-ferromagnetic materials tend to have paired electrons in each orbital or very less unpaired electrons.

Example - Neon, its atomic number is 10 and all the electrons are pared. Now, Aluminum. Its atomic number is 13 with the electronic configuration 3</span>p^{1}<span> i.e. only one unpaired electron in the p- orbital. Now, consider iron its atomic number is 26 and its configuration is 3</span>d^{6}. It has more number of unpaired electrons.  Thus, neon is non-magnetic, aluminum is also non-magnetic but iron is magnetic.
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1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

  • <u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L  

V (final volume) = 473 mL → 0.473 L  

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)  

P (final pressure) = ? (in atm)

  • <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

P_0*V_0 = P*V

1*1 = P*0.473

1 = 0.473\:P

0.473\:P = 1

P = \dfrac{1}{0.473}

\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

<u><em>Answer:  </em></u>

<u><em>The new pressure of the gas is 2.11 atm  </em></u>

___________________________________

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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What would the word equation be?
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What kind of orbital is occupied by the lone pair electrons in caffeine molecule?
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Answer:

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