A then c then b then d but it might be mising a step
I’m confused what exactly your question is?
Answer:
a) t = 56.34 minutes
b) v = 5.32mph
c) t = 47.22 minutes
d) v = 6.35 mph
Explanation:
Given;
The speed of Ilya and Anya are
Run = 8.90mph
Walk = 3.80mph
distance = 5.00 miles
a) anya walk half the distance and run half the distance.
Speed = distance/time
time = distance/speed
t1 = 5×0.5/3.80 = 0.658hr
t2 = 5×0.5/8.90 = 0.281hr
t = t1 + t2 = 0.658+0.281 = 0.939hr × 60minutes/hr
t = 56.34 minutes
b) average speed = total distance/total time taken
v = 5.00miles/0.939hr = 5.32mph
c) Ilya walk half the time and run half the time.
t1 = t2 = t/2
Distance = speed × time
Substituting the values.
5 = 3.80(t/2) + 8.90(t/2)
5 = 12.70(t/2)
t = 10/12.70
t = 0.787 hr × 60 minutes/hr
t = 47.22 minutes
d) average speed = 5miles/0.787hr
v = 6.35 mph
Initial velocity of the object: 5 m/s
Explanation:
The figure in the problem is missing: find it in attachment.
The graph in the figure represents the velocity of an object (v) versus the time passed (t).
Here we are asked to find the initial velocity of the object.
This means that we have to find the velocity of the object when the time is zero, so when
t = 0
By looking at the corresponding value on the y-axis (velocity), we see that when t = 0, then
v = 5 m/s
Therefore, the initial velocity of the object is 5 m/s.
Learn more about velocity:
brainly.com/question/5248528
#LearnwithBrainly
Answer:
B. a region of similarly oriented electrons in motion
Explanation: