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Dmitriy789 [7]
4 years ago
11

A 5 kg object is dropped from the top of a 40 m tall building. What is its initial potential energy? What is its velocity the in

stant it hits the ground? What is its velocity after it has fallen 25 m?
Physics
1 answer:
Katarina [22]4 years ago
5 0

Answer:

GPE = mgh = 5.00 kg .

 2.20 + 0.30 m = 122.5 J

Explanation:

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Ilya and Anya each can run at a speed of 8.90mph and walk at a speed of 3.80mph . They set off together on a route of length 5.0
jekas [21]

Answer:

a) t = 56.34 minutes

b) v = 5.32mph

c) t = 47.22 minutes

d) v = 6.35 mph

Explanation:

Given;

The speed of Ilya and Anya are

Run = 8.90mph

Walk = 3.80mph

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a) anya walk half the distance and run half the distance.

Speed = distance/time

time = distance/speed

t1 = 5×0.5/3.80 = 0.658hr

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t = 56.34 minutes

b) average speed = total distance/total time taken

v = 5.00miles/0.939hr = 5.32mph

c) Ilya walk half the time and run half the time.

t1 = t2 = t/2

Distance = speed × time

Substituting the values.

5 = 3.80(t/2) + 8.90(t/2)

5 = 12.70(t/2)

t = 10/12.70

t = 0.787 hr × 60 minutes/hr

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5 0
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Initial velocity of the object: 5 m/s

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The figure in the problem is missing: find it in attachment.

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t = 0

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Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

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